1. A chem 101 student dissolves 10.6 g of hydrosulfuric acid (H₂S) in 120 mL of water. Calculate the pH. 10-8 Ka = 9.1 HS (aq) H,S(aq) + H,O(1) H,O*(aq) +

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**Weak Acid Equilibria**

1. A Chem 101 student dissolves 10.6 g of hydrosulfuric acid (H₂S) in 120 mL of water. Calculate the pH.  
   \( K_a = 9.1 \times 10^{-8} \)

\[ \text{H}_2\text{S(aq)} + \text{H}_2\text{O(l)} \rightarrow \text{H}_3\text{O}^+\text{(aq)} + \text{HS}^-\text{(aq)} \]

This task involves calculating the pH of a weak acid solution by applying the concept of acid dissociation constant (\( K_a \)). The reaction shows hydrosulfuric acid reacting with water to produce hydronium ions and bisulfide ions, indicating an equilibrium setup.
Transcribed Image Text:**Weak Acid Equilibria** 1. A Chem 101 student dissolves 10.6 g of hydrosulfuric acid (H₂S) in 120 mL of water. Calculate the pH. \( K_a = 9.1 \times 10^{-8} \) \[ \text{H}_2\text{S(aq)} + \text{H}_2\text{O(l)} \rightarrow \text{H}_3\text{O}^+\text{(aq)} + \text{HS}^-\text{(aq)} \] This task involves calculating the pH of a weak acid solution by applying the concept of acid dissociation constant (\( K_a \)). The reaction shows hydrosulfuric acid reacting with water to produce hydronium ions and bisulfide ions, indicating an equilibrium setup.
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