Certainly! Here is the transcription of the provided image text along with an explanation suited for an educational website:---### Carnot Engine Thermodynamics1. A Carnot engine operates between reservoirs at 610 K and 315 K. If the engine absorbs 75 J per cycle at the hot reservoir.Calculate:(a) **The efficiency, \( e \), of the engine:**\[ e = \ \] [Input Box](b) **The work output per cycle:**\[ W_{\text{per cycle}} = \ \] [Input Box] J---The image provided shows a problem related to a Carnot engine, a theoretical thermodynamic cycle proposed by Nicolas Léonard Sadi Carnot. According to Carnot's theorem, no engine operating between two heat reservoirs can be more efficient than a Carnot engine operating between the same reservoirs.- **Efficiency (\( e \)):** The efficiency of a Carnot engine is determined by the temperatures of the hot (\( T_H \)) and cold (\( T_C \)) reservoirs. It is given by the formula: \[ e = 1 - \frac{T_C}{T_H} \] where \( T_H \) is the absolute temperature of the hot reservoir, and \( T_C \) is the absolute temperature of the cold reservoir.- **Work output per cycle:** The work output (\( W_{\text{per cycle}} \)) is related to the engine efficiency and the heat absorbed from the hot reservoir (\( Q_H \)). It can be calculated using: \[ W_{\text{per cycle}} = e \times Q_H \] where \( Q_H \) is the heat absorbed per cycle at the hot reservoir.Here, the temperatures and the heat absorbed are provided:- \( T_H = 610 \) K- \( T_C = 315 \) K- \( Q_H = 75 \) JYou can calculate the values by plugging in the numbers into the formulas provided.This exercise helps understand the fundamental principles of thermodynamics and the efficiency limits of heat engines.

Write the given values with the suitable variables. T1=610 KT2=315 KQA/cyc=75 J Here, T1, T2, and…

1. A Carnot engine operates between reservoirs at 610 and 315 K. If the engine absorbs 75J per cycle at the hot reservoir. Calculate (a) The efficiency, e, of the engine e= (b) The work output per cycle W. = per cycle

1. A Carnot engine operates between reservoirs at 610 and 315 K. If the engine absorbs 75J per cycle at the hot reservoir. Calculate (a) The efficiency, e, of the engine e= (b) The work output per cycle W. = per cycle

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A Carnot engine is operated between two energy tanks with temperatures of 450 K and 350 K. and they…

A: For Carnot engine: TH = 450 K TL = 350 K Heat received QH = 1000 J Find: a- how much energy the…

Q: Carnot engines can achieve the maximum theoretically possible efficiency for a heat engine.…

Q: The efficiency of a Carnot cycle is Te ec =1- Th (a) If an engine operating between heat reservoirs…

A: Given, An engine operating between heat reservoirs at,TC =293 KTH = 473 KHeat extracted, QH = 1000 J…

Q: A certain gasoline engine has an efficiency of 37.3%. What would the hot reservoir temperature be…

Q: A Carnot engine is running at 30% efficiency and at a rate of 12 cycles/s. It absorbs 1000 J of…

A: Given data as per question efficiency =30% Heat Absorb =1000 j Calculations Efficiency(η)= 1−T2T1η=…

Q: A heat engine operates in a Carnot cycle between 70.0°C and 345°C. It absorbs 20,800 J of energy per…

Q: An ideal gas is taken through any four stage engine cycle ABCDA. What can you say about the entropy…

A: Here given a four stage engine cycle ABCDA. We have to talk about the entropy of the cycle and cycle…

Q: 12. A Carnot ideal heat engine has its high temperature reservoir at 620 K. During each cycle this…

Q: A thermal cycle has an efficiency equal to 45.0 % of that a Carnot engine that operates between the…

Q: 49. . A Carnot engine with an efficiency of 40% oper- ates with a low-temperature reservoir at 40 °C…

Q: 8. Suppose the 1,000 kJ is needed to raise the 12 kg of now gaseous nitrogen N, from boiling…

A: Given: E=1000 kJ Ti=-196+273= 77 K Tf=20+273=293 K

Q: (a) What is the mechanical power output of this engine kW (b) How much energy does it expel in each…

A: GivenT1=74°CT2=360°CQ1=21600 Jt=3 s

Q: A Carnot engine operates between temperatures of 480 K and 400 K and does 160 J of work in each…

A: Given data *The hot reservoir temperature is T1 = 480 K *The cold reservoir temperature is T2 = 400…

Q: 4. Consider a heat engine comprising two isochores and two isobars, as in the diagram below. Suppose…

Q: Equivalence of Carnot and Ideal gas Temperature Scale. Consider a Carnot engine working between…

Q: 4. Consider a heat engine comprising two isochores and two isobars, as in the diagram below. Suppose…

Q: A Carnot engine has a cycle with a high temperature of 900 K and a low temperature of 250 K. If the…

Q: If the cold temperature reservoir of a Carnot engine is held at a constant 324 K , what temperature…

A: Given data: Cold temperature (TC) = 324 K Efficiency (n) = 0.61 Required:. The hot temperature (TH)

Q: in a Carnot engine the temperatures TH and TL have values of 250°C and 150°C. What efficiency, e,…

A: The Carnot efficiency of a heat engine cycle is the maximum theoretical efficiency a heat engine can…

Q: Problem 1: Otto cycle Prove directly (by calculating the heat taken in and the heat expelled) that…

A: Process 1-2 is adiabatic compression and 3-4 is adiabatic expansion. Heat is taken in during the…

Q: heat absorbed in a carnot cycle to the warm reservoir, if the system has an efficiency if 25…

A: Given values:- The efficiency of the system,(η)=25 %=0.25 ----(1) Heat deposited to the cold…

Q: A Carnot engine is running at 30% efficiency and at a rate of 12 cycles/s. It absorbs 1000 J of…

Q: An ideal gas is taken through a Carnot cycle. The isothermal expansion occurs at 250°C, and the…

A: Higher temperature T1=250oC=523 K, lower temperature T2=50oC=323 K, amount of heat extracted from…

Q: 56. GO A Carnot engine has an efficiency of 0.40. The Kelvin temperature of its hot reservoir is…

A: The efficiency of the Carnot engine can be given as, Here, Th denotes the temperature of the hot…

Q: 7. A refrigerator operating on the reversed Carnot cycle has a measured work input of 200 kW and…

Q: A heat engine is operating on a carnot cycle a has a thermal efficiency of 58%. The waste heat fr…

Q: A heat engine with efficiency 10 percent of a Carnot engine operating between a high temperature of…

A: Solution: Given: η1 = efficiency of heat engine = 10% of η2 η2 = efficiency of Carnot engine…

Q: A Carnot engine operates between reservoirs at 630 and 320 K. If the engine absorbs 160 J per cycle…

A: The following question can be solved as follows

Q: What is the total entropy change if a 0.440 efficiency engine takes 3.78E3 J of heat from a 348 degC…

A: To calculate the total entropy change, we can use the equation:ΔS = Q / Twhere ΔS is the total…

Question

Certainly! Here is the transcription of the provided image text along with an explanation suited for an educational website:

---

### Carnot Engine Thermodynamics

1. A Carnot engine operates between reservoirs at 610 K and 315 K. If the engine absorbs 75 J per cycle at the hot reservoir.

Calculate:

(a) **The efficiency, \( e \), of the engine:**

\[ e = \ \] [Input Box]

(b) **The work output per cycle:**

\[ W_{\text{per cycle}} = \ \] [Input Box] J

---

The image provided shows a problem related to a Carnot engine, a theoretical thermodynamic cycle proposed by Nicolas Léonard Sadi Carnot. According to Carnot's theorem, no engine operating between two heat reservoirs can be more efficient than a Carnot engine operating between the same reservoirs.

- **Efficiency (\( e \)):** The efficiency of a Carnot engine is determined by the temperatures of the hot (\( T_H \)) and cold (\( T_C \)) reservoirs. It is given by the formula:
\[
e = 1 - \frac{T_C}{T_H}
\]
where \( T_H \) is the absolute temperature of the hot reservoir, and \( T_C \) is the absolute temperature of the cold reservoir.

- **Work output per cycle:** The work output (\( W_{\text{per cycle}} \)) is related to the engine efficiency and the heat absorbed from the hot reservoir (\( Q_H \)). It can be calculated using:
\[
W_{\text{per cycle}} = e \times Q_H
\]
where \( Q_H \) is the heat absorbed per cycle at the hot reservoir.

Here, the temperatures and the heat absorbed are provided:

- \( T_H = 610 \) K
- \( T_C = 315 \) K
- \( Q_H = 75 \) J

You can calculate the values by plugging in the numbers into the formulas provided.

This exercise helps understand the fundamental principles of thermodynamics and the efficiency limits of heat engines.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

6. A heat engine consists of the cycle p shown for 3 moles of an ideal 2p monatomic gas. It starts at point 1 with pressure p and volume V; it goes via an isochoric (constant 1 volume) process from point 1 to 3 point 2 until the pressure doubles; it then goes from point 2 to point 3 via an adiabatic process; finally it goes V from point 3 to point 1 via an isothermal process. А. I What is the volume of the gas at point 3? Express your answer in terms of V (the volume of the gas at point 1). В. What are W12, W23, and W31? Express your answer in terms of p, V. 2.
A heat engine provides a net power output of 14 kW and has an efficiency of 23 %. The engine rejects 1200 J of energy per cycle to a low temperature reservoir. a)Determine the amount of heat delivered to the engine from the high temperature reservoir per second. Your answer should be in units of Watts. b)Determine the required number of cycles per minute executed.
A gasoline engine has a compression ratio of 6.00 and uses a gas for which ? = 1.40. (a) What is the efficiency of the engine if it operates in an idealized Otto cycle? %(b) If the actual efficiency is 18.0%, what fraction of the fuel is wasted as a result of friction and energy losses by heat that could by avoided in a reversible engine? (Assume complete combustion of the air-fuel mixture.) %
A thermal cycle has an efficiency equal to 45.0 % of that a Carnot engine that operates between the temperature extremes of the thermal cycle, a low of -70.0 degrees C and a high of 60.0 degrees C. If 9,000.0 J of energy flow into the system at the high temperature in one cycle, how much work is done in the cycle? HHH Kimamey Your Answer: Caps Lock Type here to search Answer JANG UGLE (O 260LCH A N 7 3 X C 4 C units O 5 99+ 113 V B 8 N K M C83°F Mostly sunny l 11:13 8/8/2
Consider a heat engine with a cycle described by the figure, with the volume and pressure at points A, B, C, and D given below. VA = 0.95 × 10-3 m3VB = 3.5 × 10-3 m3PA = 2.65 × 106 N/m2PB = 2.37 × 106 N/m2PC = 0.75 × 106 N/m2PD = 1.29 × 106 N/m2 a)Calculate the net work output, in joules, of the heat engine following path ABCDA.
D) How much work does this engine do ln one cycle? 3- A gas is compressed at a constant pressure of 1.2 Pa from 0.008 m³ to 0.002 m3. In the process, 130 J of energy leaves the gas by heat. (a) What is the work done on the gas? (b) What is the change in its internal energy?
A clear detailed answer would be great to understanding the question and also how to solve it!
Problem #8 In one cycle of an engine, 1.80 kJ of energy is absorbed from a hot reservoir at 280°C, and 1.15 kJ of energy is expelled to a cold reservoir at 25.0°C. a) How much work (in J) is done by the engine in each cycle? b) What is the engine's efficiency? c) How does this compare to the Carnot Efficiency?