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1. A ball of mass m 0.55 kg, starting from rest, falls a vertical distance h = 75.0 cm before striking a 15M O. vertically mounted spring, which is then compressed a distance = 14.5 cm. , 14 Sm a) Is the mechanical energy of the spring-mass system conserved? Explain. yes the mecha ical E is canserveD. Wnc =0 because the block ion'1 contact wl.surface. b) Derive the algebraic expression for the spring constant using the provided information. %3D • + mgki +ż Ky - ky²) = Ky2 hity: ot mghi = 2 (mg(h;+Y) 2mgchity) c) Calculate the spring constant. O + K = 2mg (hity) 0.995 %3D 93 K= 2mg (nity) 9.4451 459,887 K= 2(0.55) (9, $) (0.895) (6.145)2 o.021 submerged under oil and in a static

1. A ball of mass m 0.55 kg, starting from rest, falls a vertical distance h = 75.0 cm before striking a 15M O. vertically mounted spring, which is then compressed a distance = 14.5 cm. , 14 Sm a) Is the mechanical energy of the spring-mass system conserved? Explain. yes the mecha ical E is canserveD. Wnc =0 because the block ion'1 contact wl.surface. b) Derive the algebraic expression for the spring constant using the provided information. %3D • + mgki +ż Ky - ky²) = Ky2 hity: ot mghi = 2 (mg(h;+Y) 2mgchity) c) Calculate the spring constant. O + K = 2mg (hity) 0.995 %3D 93 K= 2mg (nity) 9.4451 459,887 K= 2(0.55) (9, $) (0.895) (6.145)2 o.021 submerged under oil and in a static

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DITUI AUL 3IEPS TO EARN FULL CREDIT! 1. A ball of mass m = 0.55 kg, starting from rest, falls a vertical distance h = 75.0 cm before striking a 75M o. vertically mounted spring, which is then compressed a distance = 14.5 cm. , 14 Sm a) Is the mechanical energy of the spring-mass system conserved? Explain. sut sah because mechanical E is canserves. Wnc =0 the block ion' contact wl.surface. in nイ b) Derive the algebraic expression for the spring constant using the provided information. o + mghi = o + mgkE + Ź ky" 2 (mg(h;tY). 2mg Chity) =' Ky? c) Calculate the spring constant. hity: %3D K = 2 mg (hity) 0.995 %3D K= 2mg (nitu4) 9.4451 K = 459,887 K- 2(0.55) (9,8)(0.895) (6.145)2 0.021 っフ 2. An object of mass 1.50 kg and density 3500 kg/m is completely submerged under oil and in a static equilibrium hanging from a spring (k = 150 N/m) that is fixed from the top as shown in the figure. (The density of oil is 920 kg/m®). a) Draw a free body diagram for the suspended object.
Transcribed Image Text:DITUI AUL 3IEPS TO EARN FULL CREDIT! 1. A ball of mass m = 0.55 kg, starting from rest, falls a vertical distance h = 75.0 cm before striking a 75M o. vertically mounted spring, which is then compressed a distance = 14.5 cm. , 14 Sm a) Is the mechanical energy of the spring-mass system conserved? Explain. sut sah because mechanical E is canserves. Wnc =0 the block ion' contact wl.surface. in nイ b) Derive the algebraic expression for the spring constant using the provided information. o + mghi = o + mgkE + Ź ky" 2 (mg(h;tY). 2mg Chity) =' Ky? c) Calculate the spring constant. hity: %3D K = 2 mg (hity) 0.995 %3D K= 2mg (nitu4) 9.4451 K = 459,887 K- 2(0.55) (9,8)(0.895) (6.145)2 0.021 っフ 2. An object of mass 1.50 kg and density 3500 kg/m is completely submerged under oil and in a static equilibrium hanging from a spring (k = 150 N/m) that is fixed from the top as shown in the figure. (The density of oil is 920 kg/m®). a) Draw a free body diagram for the suspended object.
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