1. 25.0 kg of liquid lava at 1520.0°C flows into the 35.0°C water surrounding a volcanic island, vaporizing the water into a beautiful display of steam at 100.0°C. a. Calculate the heat produced when the 25.0 kg of liquid lava at 1520.0°C drops to 1170.0°C. Assume the heat capacity of liquid lava is 840. J/kg*K.
1. 25.0 kg of liquid lava at 1520.0°C flows into the 35.0°C water surrounding a volcanic island, vaporizing the water into a beautiful display of steam at 100.0°C. a. Calculate the heat produced when the 25.0 kg of liquid lava at 1520.0°C drops to 1170.0°C. Assume the heat capacity of liquid lava is 840. J/kg*K.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Educational Content: Heat Transfer in Volcanic Activity
#### Problem Statement:
1. **Scenario**:
- 25.0 kg of liquid lava at 1520.0°C flows into 35.0°C water surrounding a volcanic island.
- This interaction vaporizes the water, creating steam at 100.0°C.
2. **Task**:
- Calculate the heat produced when the 25.0 kg of liquid lava at 1520.0°C cools down to 1170.0°C.
- Assume the specific heat capacity of liquid lava is 840 J/kg·K.
#### Explanation:
This exercise involves the calculation of heat transfer from hot lava to its surroundings, specifically during cooling. The heat produced can be calculated using the formula for heat transfer:
\[ Q = mc\Delta T \]
Where:
- \( Q \) is the heat produced (in Joules),
- \( m \) is the mass of the lava (in kilograms),
- \( c \) is the specific heat capacity (in J/kg·K),
- \(\Delta T\) is the change in temperature (in Kelvin or °C).
This problem emphasizes understanding the thermal interactions in a natural event like a volcanic eruption, illustrating how energy is transferred from lava to surrounding elements.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf8e267e-10e5-42d7-8fd7-a8f3672a74ed%2Ffeb9161a-4954-46e6-9d1d-1ae584510347%2Fdzqvm4l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Educational Content: Heat Transfer in Volcanic Activity
#### Problem Statement:
1. **Scenario**:
- 25.0 kg of liquid lava at 1520.0°C flows into 35.0°C water surrounding a volcanic island.
- This interaction vaporizes the water, creating steam at 100.0°C.
2. **Task**:
- Calculate the heat produced when the 25.0 kg of liquid lava at 1520.0°C cools down to 1170.0°C.
- Assume the specific heat capacity of liquid lava is 840 J/kg·K.
#### Explanation:
This exercise involves the calculation of heat transfer from hot lava to its surroundings, specifically during cooling. The heat produced can be calculated using the formula for heat transfer:
\[ Q = mc\Delta T \]
Where:
- \( Q \) is the heat produced (in Joules),
- \( m \) is the mass of the lava (in kilograms),
- \( c \) is the specific heat capacity (in J/kg·K),
- \(\Delta T\) is the change in temperature (in Kelvin or °C).
This problem emphasizes understanding the thermal interactions in a natural event like a volcanic eruption, illustrating how energy is transferred from lava to surrounding elements.
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