(1) Which equation could represent the circle that has the center at A = (-2, 3) and a point B = (6, -3) on the circle? (A) (x + 2)² + (y – 3)² = 25 (C) (x – 2)? + y ? = 100 (B) (x + 2)? + (y - 3)² = 100 (D) (x – 2)? + y? = 25 %3D %3D

Q: A line passes through the center of a circle and intersects it at points (-1,2) and (5,10). What is…

A: equation of line passing through points (x1, y1) and (x2, y2) is:  y-y1=y2-y1x2-x1(x-x1)    Equation…

Q: x- - Consider the equations 2x + 4y = 8 and y = 10. Select the point where the graphs of these two…

A: Point of intersection is the point which lies on both lines, simply they are values of x and y that…

Q: Find the point on the line 3x + 6y +2=0 which is closest to the point (2,-2). Answer is

A: Foot of perpendicular

Q: Determine if the following points are on the graph of the equation 2x-y=6 . (a) (2,3) (b)(2, -2)

A: The given equation is 2x-y=6

Q: The center of the circle (x+3)2+(y-2)2=13 is(3,-2)

A: The given circle equation is (x+3)2+(y-2)2=13

Q: the circle (x-2)^2+(y-5)^2=16 is moved up 3 units and to the left 1 unit. where is the center of the…

A:

Q: Find the equation of the circle which passes through (10:2), (9.-3) and the centre of the circle…

A:

Q: Write the equation of the circle in standard form, (x - h)2 + (y - k)2 = r2. (r-(O) + (- - (O) - 2

A: The equation of circle in standard form is x-h2+y-k2=r2, where (h,k) is the center and r is the…

Q: Which point is on the circle with equation (x-4)^2 + (y+3)^2 = 9 ?

A: The equation of circle is given as (x-4)2 + (y+3)2 =9, it can be written as (x-4)2 + (y+3)2…

Q: (-2,4) parallel to y=-3/2x+3

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Q: Describe the shape of the graph of y=(x+2)(xto the power of 2-1) with regards to its intercepts

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Q: a circle centered at the origin has an equation x²+y²=64, what is the equation of the circle after…

A:

Q: Vhat is the equation of a circle with center (3, –7) that goes through the oint (1, 1)? D (x – 3)2 +…

A:

Q: What is the equation of circles passing through (1,-1), and touching the lines 4x+3y+5=0 and…

A: