Vhat is the equation of a circle with center (3, –7) that goes through the oint (1, 1)? D (x – 3)2 + (y + 7)² = 32 O (x – 3)² + (y+ 7)² = 68 D (x + 3)2 + (y – 7)² = 52 O (x + 3)² + (y – 7)² = 40

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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What is the equation of a circle with center (3,−7) that goes through the point (1,1)?

Question 5
What is the equation of a circle with center (3, –7) that goes through the
point (1, 1)?
O (x – 3)2 + (y + 7)² = 32
O (x – 3)2 + (y+ 7)² = 68
O (x + 3)2 + (y – 7)² = 52
O (x + 3)2 + (y – 7)² = 40
%3D
Transcribed Image Text:Question 5 What is the equation of a circle with center (3, –7) that goes through the point (1, 1)? O (x – 3)2 + (y + 7)² = 32 O (x – 3)2 + (y+ 7)² = 68 O (x + 3)2 + (y – 7)² = 52 O (x + 3)2 + (y – 7)² = 40 %3D
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