1) Two rods have the same mass and length, but the mass is distributed differently. One rod has the mass concentrated at the ends and the other has the mass concentrated at the center. The two rods are held at their centers and rotated back and forth. Which one is easier to rotate? What is a possible physical explanation for this?

1) Two rods have the same mass and length, but the mass is distributed differently. One rod has the mass concentrated at the ends and the other has the mass concentrated at the center. The two rods are held at their centers and rotated back and forth. Which one is easier to rotate? What is a possible physical explanation for this?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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1) Blocks of mass m1 and m2 are connected by a massless string that pulls over the pulley in the figure. Initially, the system is at rest. The table is frictionless. The pulley is frictionless, but it does have mass Mp and radius R. The moment of inertia of the pulley is Ipulley=2/3MR2 (note that this is DIFFERENT than what we have used in the practice test examples). Consider that at t=0 (initially) m2 is H meters above the ground. In this problem, H=60 cm., R=7 cm., Mpulley=1.8 kg, m1=6 kg, and m2=15 kg. (a)Using those energies from the above table that apply to this question and identifying the ground as the point of "zero height", use "conservation of energy" to find the speed of m2 just as it hits the ground. There are no non-conservative forces outside of the system to consider, so Ef=Ei (the initial state is when the system is at rest and m2 is hanging H meters above the ground, and the final state is when the system is moving (both blocks are moving and the pulley is spinning)…