(1) Three balls A, B and C, A is triple as likely to choose as B and B triple as likely to choose as C. The probabilities of their choosing respectively are 8 (a) P(A) = 13 2 P(B) =- 13 3 P(C) =- 13 5 P(B) =- 13 7 P(C) = 13 (b) Р(А) %3D 13 8 P(B) = 3 PC) 27 (c) P(A) = 27 27 2 P(B) = 7 , Р(С)-. 27 18 (d) P(A)= 27 27 1 P(B) = 3) = P(C) = 9. (e) P(A) = 13 13 13 (f) None of these a is the correct answer b is the correct answer c is the correct answer d is the correct answer e is the correct answer

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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(1) Three balls A, B and C, A is triple as likely to choose as B and B triple as
likely to choose as C. The probabilities of their choosing respectively are
8
Р(В) 3
3
P(C) =
13
(а) Р(А) %3D
13
13
P(B) =-
13
7
P(C) =-
13
(b) Р(А) —
13
8
P(B) =
3
P(C) =:
27
(c) P(A) =
27
27
2
P(B) =-
27
7
P(C) =
27
18
(d) P(A) =
27
1
(е) Р(А) —
13
3
Р(В) —
13
9
P(C) =-
13
(f) None of these
a is the correct answer
b is the correct answer
c is the correct answer
d is the correct answer
e is the correct answer
f is the correct answer
Transcribed Image Text:(1) Three balls A, B and C, A is triple as likely to choose as B and B triple as likely to choose as C. The probabilities of their choosing respectively are 8 Р(В) 3 3 P(C) = 13 (а) Р(А) %3D 13 13 P(B) =- 13 7 P(C) =- 13 (b) Р(А) — 13 8 P(B) = 3 P(C) =: 27 (c) P(A) = 27 27 2 P(B) =- 27 7 P(C) = 27 18 (d) P(A) = 27 1 (е) Р(А) — 13 3 Р(В) — 13 9 P(C) =- 13 (f) None of these a is the correct answer b is the correct answer c is the correct answer d is the correct answer e is the correct answer f is the correct answer
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