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1) This problem will investigate some of the difference between electric and magnetic fields. As such we have a positive charge that is moving with the following information. 0.17 m 1,450 m/s 11.5 µC a. At the location of the indicated "x" give the direction of both the Electric and Magnetic field as produced by the moving charge. b. It is relativly easy to "stop" electric fields (remember the Faraday Effect). It is however very difficult to stop magnetic fields. What property of magnetic fields (that is different from electric fields) would cause such a difference? What is the physical reason for this property of magnetic fields? c. It is possible to find the size magnetic field from a moving charge by the following formula : moving point chargel Hoqv 4tr2° Determine the size of the magnetic field at the "x".

1) This problem will investigate some of the difference between electric and magnetic fields. As such we have a positive charge that is moving with the following information. 0.17 m 1,450 m/s 11.5 µC a. At the location of the indicated "x" give the direction of both the Electric and Magnetic field as produced by the moving charge. b. It is relativly easy to "stop" electric fields (remember the Faraday Effect). It is however very difficult to stop magnetic fields. What property of magnetic fields (that is different from electric fields) would cause such a difference? What is the physical reason for this property of magnetic fields? c. It is possible to find the size magnetic field from a moving charge by the following formula : moving point chargel Hoqv 4tr2° Determine the size of the magnetic field at the "x".

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1) This problem will investigate some of the difference between electric and magnetic fields. As such we have a positive charge that is moving with the following information. 0.17 m 1,450 m/s 11.5 µC a. At the location of the indicated "x" give the direction of both the Electric and Magnetic field as produced by the moving charge. b. It is relativly easy to "stop" electric fields (remember the Faraday Effect). It is however very difficult to stop magnetic fields. What property of magnetic fields (that is different from electric fields) would cause such a difference? What is the physical reason for this property of magnetic fields? c. It is possible to find the size magnetic field from a moving charge by the following formula : Ho qu В тoving point charge 4tr2° Determine the size of the magnetic field at the “x". d. It is much more difficult to “stop" magnetic fields relative to electric fields. Despite this fact, magnetic fields are not something we normally worry about with wireless signals and electronics. Use your answer from part "c" and the fact that the electric field at the location of "x"is : 3.6x106 V/m to explain why.
Transcribed Image Text:1) This problem will investigate some of the difference between electric and magnetic fields. As such we have a positive charge that is moving with the following information. 0.17 m 1,450 m/s 11.5 µC a. At the location of the indicated "x" give the direction of both the Electric and Magnetic field as produced by the moving charge. b. It is relativly easy to "stop" electric fields (remember the Faraday Effect). It is however very difficult to stop magnetic fields. What property of magnetic fields (that is different from electric fields) would cause such a difference? What is the physical reason for this property of magnetic fields? c. It is possible to find the size magnetic field from a moving charge by the following formula : Ho qu В тoving point charge 4tr2° Determine the size of the magnetic field at the “x". d. It is much more difficult to “stop" magnetic fields relative to electric fields. Despite this fact, magnetic fields are not something we normally worry about with wireless signals and electronics. Use your answer from part "c" and the fact that the electric field at the location of "x"is : 3.6x106 V/m to explain why.
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