1) The perimeter of a given square P can be represented by the function P(A) = 4√Ā where A is the area of the square. The graph of the function P is shown for 0 ≤ A ≤ 25. Perimeter (P) 20 10- a) Write down the value of P(25). The range of P(A) is 0 ≤ P(A) ≤ n. 10 Area (4) 20 b) Hence write down the value of n. c) On the axes above, draw the graph of the inverse function, P-¹.
1) The perimeter of a given square P can be represented by the function P(A) = 4√Ā where A is the area of the square. The graph of the function P is shown for 0 ≤ A ≤ 25. Perimeter (P) 20 10- a) Write down the value of P(25). The range of P(A) is 0 ≤ P(A) ≤ n. 10 Area (4) 20 b) Hence write down the value of n. c) On the axes above, draw the graph of the inverse function, P-¹.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![1) The perimeter of a given square P can be represented by the function P(A) = 4√Ā where A is the area of the
square. The graph of the function P is shown for 0 ≤ A ≤ 25.
Perimeter (P)
20
10
a) Write down the value of P(25).
The range of P(A) is 0 ≤ P(A) ≤n.
10
Area (4)
20
b) Hence write down the value of n.
c) On the axes above, draw the graph of the inverse function, P-¹.
d) In the context of the question, explain the meaning of P-¹(8) = 4.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd86db678-bc86-44fd-bd72-7c276c312ad6%2F97f9790b-a111-48d5-bd66-90b984ce9207%2Fmi7kqk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1) The perimeter of a given square P can be represented by the function P(A) = 4√Ā where A is the area of the
square. The graph of the function P is shown for 0 ≤ A ≤ 25.
Perimeter (P)
20
10
a) Write down the value of P(25).
The range of P(A) is 0 ≤ P(A) ≤n.
10
Area (4)
20
b) Hence write down the value of n.
c) On the axes above, draw the graph of the inverse function, P-¹.
d) In the context of the question, explain the meaning of P-¹(8) = 4.
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