1- The mercury present in a sample with a mass equal to 0.8142 g was precipitated with an excess of paraperiodic acid (H5I06) according to the reaction below: 5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10 H* The precipitate was filtered, washed free of precipitating agent, dried and weighed to give 0.4114 g. Calculate the % of Hg and of Hg2C12 in the sample. Data: Hg = 200.59 H = 1.008 Cl = 35.45 | = 126.90 %3D O = 16.00 %3D

1- The mercury present in a sample with a mass equal to 0.8142 g was precipitated with an excess of paraperiodic acid (H5I06) according to the reaction below: 5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10 H* The precipitate was filtered, washed free of precipitating agent, dried and weighed to give 0.4114 g. Calculate the % of Hg and of Hg2C12 in the sample. Data: Hg = 200.59 H = 1.008 Cl = 35.45 | = 126.90 %3D O = 16.00 %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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