This is a test I have already taken but I am still struggling with the feedback I have received. Please help me solve questions 1 and 2. Thank you for your help. CPlease study and retake thisName Blas Manyere[1] The lengths of all hullback trout are normally distributed: N(16 inches, 3.6 inches). Thismeans that the mean length for all hullback trout is 16 inches and the standard deviation is 3.6inches.ALG 2= 16mean =Stemd D=3.616-15Z-Score 1616-16FO3.6thanFind the probability that a randomly chosen hullback trout is shorter than 15 inches,Show all your thinking.2-Score 1515-163.6Chpt 925= -0.2777noSo passQUIZmatching prob = 5000Matching prob = .3936[2] Find x. Show your thinking.Sin 33- Sin B15Side AC1516mean1ST (15-16)3,62ND find matchingprobability5000-3936 0.1064sin 33⁰-50 X = 15nixsin 33⁰x cm33°B15 cm

The lengths of hullback trout are normally distributed with mean inches and the standard deviation…

[1] The lengths of all hullback trout are normally distributed: N(16 inches, 3.6 inches), means that the mean length for all hullback trout is 16 inches and the standard deviation is 3.6 inches. Find the probability that a randomly chosen hullback trout is shorter than 15 inches, Show all your thinking.

[1] The lengths of all hullback trout are normally distributed: N(16 inches, 3.6 inches), means that the mean length for all hullback trout is 16 inches and the standard deviation is 3.6 inches. Find the probability that a randomly chosen hullback trout is shorter than 15 inches, Show all your thinking.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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