[1] The lengths of all hullback trout are normally distributed: N(16 inches, 3.6 inches), means that the mean length for all hullback trout is 16 inches and the standard deviation is 3.6 inches. Find the probability that a randomly chosen hullback trout is shorter than 15 inches, Show all your thinking.
[1] The lengths of all hullback trout are normally distributed: N(16 inches, 3.6 inches), means that the mean length for all hullback trout is 16 inches and the standard deviation is 3.6 inches. Find the probability that a randomly chosen hullback trout is shorter than 15 inches, Show all your thinking.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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This is a test I have already taken but I am still struggling with the feedback I have received. Please help me solve questions 1 and 2. Thank you for your help.
![C
Please study and retake this
Name Blas Manyere
[1] The lengths of all hullback trout are normally distributed: N(16 inches, 3.6 inches). This
means that the mean length for all hullback trout is 16 inches and the standard deviation is 3.6
inches.
ALG 2
= 16
mean =
Stemd D=3.6
16-15
Z-Score 16
16-16
FO
3.6
than
Find the probability that a randomly chosen hullback trout is shorter than 15 inches,
Show all your thinking.
2-Score 15
15-16
3.6
Chpt 9
25
= -0.2777
no
So pass
QUIZ
matching prob = 5000
Matching prob = .3936
[2] Find x. Show your thinking.
Sin 33- Sin B
15
Side AC
15
16
mean
1ST (15-16)
3,6
2ND find matching
probability
5000-3936 0.1064
sin 33⁰-
50 X = 15
nix
sin 33⁰
x cm
33°
B
15 cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F233dd85c-372f-4e28-8989-94d95de9925b%2F364bcd60-b4ed-4313-8f71-c3d7fab23462%2Ffo6ebj9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:C
Please study and retake this
Name Blas Manyere
[1] The lengths of all hullback trout are normally distributed: N(16 inches, 3.6 inches). This
means that the mean length for all hullback trout is 16 inches and the standard deviation is 3.6
inches.
ALG 2
= 16
mean =
Stemd D=3.6
16-15
Z-Score 16
16-16
FO
3.6
than
Find the probability that a randomly chosen hullback trout is shorter than 15 inches,
Show all your thinking.
2-Score 15
15-16
3.6
Chpt 9
25
= -0.2777
no
So pass
QUIZ
matching prob = 5000
Matching prob = .3936
[2] Find x. Show your thinking.
Sin 33- Sin B
15
Side AC
15
16
mean
1ST (15-16)
3,6
2ND find matching
probability
5000-3936 0.1064
sin 33⁰-
50 X = 15
nix
sin 33⁰
x cm
33°
B
15 cm
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