1-The joint distribution of X and Y is: PX,Y(0,0)=1/25, PX,Y(0,1)=a, PX,Y(0,2)=2/25 PX,Y(1,0)=a, PX,Y(1,1)=b, PX,Y(1,2)=a PX,Y(2,0)=2/25, PX,Y(2,1)=a, PX,Y(2,2)=1/25 You want "a" to make the variance of Y as minimum as possible. The variance of Y equals. Select one: a. 3/10 b. 6/25 c. 1/2 d. 3/5 e. 2/5

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Chapter1: Combinatorial Analysis
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1-The joint distribution of X and Y is:

PX,Y(0,0)=1/25, PX,Y(0,1)=a, PX,Y(0,2)=2/25

PX,Y(1,0)=a, PX,Y(1,1)=b, PX,Y(1,2)=a

PX,Y(2,0)=2/25, PX,Y(2,1)=a, PX,Y(2,2)=1/25

You want "a" to make the variance of Y as minimum as possible.

The variance of Y equals.

Select one:
a. 3/10
b. 6/25
c. 1/2
d. 3/5
e. 2/5
 
2-Suppose X ~ N(2, 9) and Y ~ N(2, 16) are independent random variables.

Then P(X + Y < 9) equals:

Select one:
a. 0.1587
b. 0.1151
c. 0.5
d. 0.8849
e. 0.8413
 
 
3-Claims for a health company insurance are exponentially distributed. An insurance company offers the subscriber two different types of insurance, class A has a coverage of 1.44. For a random loss, with a probability of 0.640. Class B has a coverage of d. with a probability of 0.512.

The value of d is:


 

Select one:
a. 2.0182
b. 2.0976
c. 2.31
d. 1.8871
e. 2.16
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