**Three-Block System Analysis**In this problem, we explore the dynamics of a three-block system set on a frictionless surface. The system includes blocks weighing 3.0 kg, 2.0 kg, and 1.0 kg. The 3.0 kg and 1.0 kg blocks are connected by a very light rope, and a force \( F = 84 \, \text{N} \) is applied directly to the 2.0 kg mass.### Objective:1. **Calculate the following:** - **Tension in the rope.** - **Force exerted on the 2.0 kg block by the 3.0 kg block.** - **Force exerted on the 3.0 kg block by the 2.0 kg block.** **Solution:** - Tension in the rope: \( 14 \, \text{N} \) - Force exerted on the 2.0 kg block by the 3.0 kg block: \( 56 \, \text{N} \) - Force exerted on the 3.0 kg block by the 2.0 kg block: \( 56 \, \text{N} \)2. **Reverse Motion Analysis:** - Assume all three blocks initially have a common speed of \( 42 \, \text{m/s} \) to the left at the moment the force \( F \) is applied. - Determine the time required for the motion of the blocks to reverse direction. **Solution:** - Time to reverse direction: \( 3.0 \, \text{s} \)### Diagram Explanation:The diagram illustrates a horizontal arrangement of the blocks:- **1.0 kg block** on the left, **3.0 kg block** on the right, and **2.0 kg block** in the center.- Block masses are depicted, and the force \( F \) is shown acting to the right on the 2.0 kg block.- The system is on a surface where friction is negligible, enabling an ideal scenario for these calculations.

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Description: **Three-Block System Analysis**In this problem, we explore the dynamics of a three-block system set on a frictionless surface. The system includes blocks weighing 3.0 kg, 2.0 kg, and 1.0 kg. The 3.0 kg and 1.0 kg blocks are connected by a very light

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(1) The 3-block system shown below is on a surface that is so slippery you may consider it to be frictionless. The 3.0 kg and 1.0 kg masses are connected by a very light rope, and a force F = 84 N force acts directly on the 2.0 kg mass as shown. (a) Calculate: the tension in the rope • the force exerted on the 2.0 kg block by the 3.0 kg block • the force exerted on the 3.0 kg block by the 2.0 kg block. [answer: tension in rope = 14 N; F30n2 = F20n3 = 56 N] (b) Suppose all three blocks had a common speed of 42 m/s to the left at the moment the force F was applied. How long will it take the motion of the blocks to reverse direction after F is applied? [answer: 3.0 s] 1.0 kg F 2.0 kg 3.0 kg

(1) The 3-block system shown below is on a surface that is so slippery you may consider it to be frictionless. The 3.0 kg and 1.0 kg masses are connected by a very light rope, and a force F = 84 N force acts directly on the 2.0 kg mass as shown. (a) Calculate: the tension in the rope • the force exerted on the 2.0 kg block by the 3.0 kg block • the force exerted on the 3.0 kg block by the 2.0 kg block. [answer: tension in rope = 14 N; F30n2 = F20n3 = 56 N] (b) Suppose all three blocks had a common speed of 42 m/s to the left at the moment the force F was applied. How long will it take the motion of the blocks to reverse direction after F is applied? [answer: 3.0 s] 1.0 kg F 2.0 kg 3.0 kg

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

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Question

**Three-Block System Analysis**

In this problem, we explore the dynamics of a three-block system set on a frictionless surface. The system includes blocks weighing 3.0 kg, 2.0 kg, and 1.0 kg. The 3.0 kg and 1.0 kg blocks are connected by a very light rope, and a force \( F = 84 \, \text{N} \) is applied directly to the 2.0 kg mass.

### Objective:
1. **Calculate the following:**
- **Tension in the rope.**
- **Force exerted on the 2.0 kg block by the 3.0 kg block.**
- **Force exerted on the 3.0 kg block by the 2.0 kg block.**

**Solution:**
- Tension in the rope: \( 14 \, \text{N} \)
- Force exerted on the 2.0 kg block by the 3.0 kg block: \( 56 \, \text{N} \)
- Force exerted on the 3.0 kg block by the 2.0 kg block: \( 56 \, \text{N} \)

2. **Reverse Motion Analysis:**
- Assume all three blocks initially have a common speed of \( 42 \, \text{m/s} \) to the left at the moment the force \( F \) is applied.
- Determine the time required for the motion of the blocks to reverse direction.

**Solution:**
- Time to reverse direction: \( 3.0 \, \text{s} \)

### Diagram Explanation:
The diagram illustrates a horizontal arrangement of the blocks:
- **1.0 kg block** on the left, **3.0 kg block** on the right, and **2.0 kg block** in the center.
- Block masses are depicted, and the force \( F \) is shown acting to the right on the 2.0 kg block.
- The system is on a surface where friction is negligible, enabling an ideal scenario for these calculations.

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