Our skier is now racing down the y = 28.3 m height and angle e = 15.9° hill again. This time there is friction on the hill. What is the coefficient of kinetic friction if her speed is now one half of what it would have been with no friction?
Our skier is now racing down the y = 28.3 m height and angle e = 15.9° hill again. This time there is friction on the hill. What is the coefficient of kinetic friction if her speed is now one half of what it would have been with no friction?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Text Explanation:**
"Our skier is now racing down the \( y = 28.3 \, \text{m} \) height and angle \( \theta = 15.9^\circ \) hill again. This time there is friction on the hill. What is the coefficient of kinetic friction if her speed is now one half of what it would have been with no friction?"
**Diagram Explanation:**
The diagram shows a skier descending a triangular slope.
- The slope has a height denoted as \( y \), measuring 28.3 meters, represented by a vertical bracket and labeled with a red \( y \) on the left side.
- The angle of the slope, \( \theta \), is 15.9 degrees, indicated in red on the slope.
- The skier is illustrated at the top of the slope, moving downwards.
The problem involves calculating the coefficient of kinetic friction on the slope, given that the skier's speed with friction is half of what it would be without friction.
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