1) Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 90.0 kg, down a 60.0° slope at a constant speed of 1.2 m/s. The friction between the sled and the snow is 44.1 Newtons. The person is lowered 30.0 meters along the steep ground (note this is not the change in height). The forces on the person are shown. a) Draw a motion diagram for the person b) Draw the energy cups c) Calculate the change in mechanical energy d) Apply (F Ax cos o) = AEmechanical And calculate the work done by each force and the tension force. T 60°

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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1) Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 90.0 kg, down a 60.0°
slope at a constant speed of 1.2 m/s. The friction between the sled and the snow is 44.1 Newtons. The
person is lowered 30.0 meters along the steep ground (note this is not the change in height). The forces
on the person are shown.
a) Draw a motion diagram for the person
b) Draw the energy cups
c) Calculate the change in mechanical energy
d) Apply (F Ax cos o) = AEmechanical
And calculate the work done by each force and the
tension force.
T
N
60°
Transcribed Image Text:1) Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 90.0 kg, down a 60.0° slope at a constant speed of 1.2 m/s. The friction between the sled and the snow is 44.1 Newtons. The person is lowered 30.0 meters along the steep ground (note this is not the change in height). The forces on the person are shown. a) Draw a motion diagram for the person b) Draw the energy cups c) Calculate the change in mechanical energy d) Apply (F Ax cos o) = AEmechanical And calculate the work done by each force and the tension force. T N 60°
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