Question 1 1) Rate from Loudest (3) to less loudest (1) the 3 following situations, explain why on each case, preferably withwave graphsSituationa) One speaker emitting a 440 hertzfrequency sound and an amplitude of 10decibels. You are standing 10 metersfrom the speakersb) Two speakers at emit the same exactsound as the speaker in (a), both aresynchronized (identical waves at thesame time) you are in between the twoakers, 10 meters from each one (theyare 20 meters apart)c) Two speakers at the same configuration,you are in between them, and they emitthe same sound with the samebandfrequency. The difference is there is adelay between the two speakers of 2.27milliseconds; this delay is exactly half aperiod of the waves.2) List two differences between sound waves and light waves3) For the wave below (a) What is the wavelength (in cm) and amplitude in dB of the wave below? (b) If the wavetravels at 4 cm/s. What is the period? What is the frequency? [note, you can use the speed of the wave to turnwavelength into period]

Since you have posted 3 different questions, we will answer first one only. Please resubmit the question for the answer of question 2. Also resend the question three with the image. We need to mention the loudest to less loudest sound for the given question.a) For situation a, there are only one speaker. That means the observer will experience the loudness of the sound from one speaker only and there will be no such interference effect. b) In situation b, both speakers are emitting same sound and the waves are synchronized which means waves are in same phase. The distance between both speaker and the observer is 10 m. Therefore the net path difference between the waves coming from both speakers to observer is zero. This means that the condition of constructive interference will be satisfied. When two waves interfere constructively, the amplitude of the both waves adds up to produce the resulting wave. Hence the observer will experience twice loudness as compared to situation a. c) In situation c, again the speakers are of same configuration. The external path difference is zero as the observer is standing exactly in between. But this time there is a time lag between the speakers of 2.27 ms which is exactly equal to the half period of the sound waves. Now full period T corresponds to a phase difference of 2π, but a half period T/2 corresponds to a phase difference .π If two waves interfere each other with a phase difference π in between them, the condition of destructive interference gets satisfied. Thus both waves will cancel each other at the point of interference and we will get negligible loudness. Graph:So the loudness order will be Situation b > situation a > situation c