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1 - R 0.632/9 0.368/, 7 = L/R 21 3t 47 T = L/R 2t 3t 4t (a) (b) (c)

1 - R 0.632/9 0.368/, 7 = L/R 21 3t 47 T = L/R 2t 3t 4t (a) (b) (c)

Physics for Scientists and Engineers: Foundations and Connections
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter15: Fluids
Section: Chapter Questions
Problem 7PQ
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The 5.00 A current through a 1.50 H inductor is dissipated by a 2.00 Ω resistor in a circuit like that in Figure 23.44 with the switch in position 2.

(a) What is the initial energy in the inductor? (b) How long will it take the current to decline to 5.00% of its initial value?

1 - R 0.632/9 0.368/, 7 = L/R 21 3t 47 T = L/R 2t 3t 4t (a) (b) (c)
Transcribed Image Text:1 - R 0.632/9 0.368/, 7 = L/R 21 3t 47 T = L/R 2t 3t 4t (a) (b) (c)
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