1 pts Question 1 Let S be the part of the surface z = 16 - x² - y² that is above z = 0. Then the value of sin n ( // (2z + 1) ds) is S 0.875 0.758 -0.087 0.458 0.606 0.027 -0.690 0.663

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Chapter6: Topics In Analytic Geometry
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1 pts
Question 1
Let S be the part of the surface z = 16 - x² - y² that is above z = 0. Then the value of sin n ( // (2z + 1) ds) is
S
0.875
0.758
-0.087
0.458
0.606
0.027
-0.690
0.663
Transcribed Image Text:1 pts Question 1 Let S be the part of the surface z = 16 - x² - y² that is above z = 0. Then the value of sin n ( // (2z + 1) ds) is S 0.875 0.758 -0.087 0.458 0.606 0.027 -0.690 0.663
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