1 points Save Answer A 1450 kg car traveling initially at vcj = 23 m/s in easterly direction crashes into the back of a 6500 kg truck moving in the same direction at vT j = 13 m/s as shown in figure below. The velocity of the car immediately after the collision is Vcf = 15 m/s to the east. The velocity of the truck immediately after the collision (VTf) is: (Consider: East direction points to +x axis direction)

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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A 1450 kg car traveling initially at vcj = 23 m/s in easterly direction crashes into the back
of a 6500 kg truck moving in the same direction at vT j = 13 m/s as shown in figure below.
The velocity of the car immediately after the collision is Vcf = 15 m/s to the east. The
velocity of the truck immediately after the collision (VTf) is:
(Consider: East direction points to +x axis direction)
Before
After
O a. +11.22 m/s
Ob.+14.78 m/s
C. +21.48 m/s
d. +29.25 m/s
Transcribed Image Text:1 points Save Answer A 1450 kg car traveling initially at vcj = 23 m/s in easterly direction crashes into the back of a 6500 kg truck moving in the same direction at vT j = 13 m/s as shown in figure below. The velocity of the car immediately after the collision is Vcf = 15 m/s to the east. The velocity of the truck immediately after the collision (VTf) is: (Consider: East direction points to +x axis direction) Before After O a. +11.22 m/s Ob.+14.78 m/s C. +21.48 m/s d. +29.25 m/s
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