(1 point) Solve the linear system below by substitution. х — 2у — 2 -5 2x + y + z -2 -2y – z Note: your answers must be fractions (decimals are not allowed).
(1 point) Solve the linear system below by substitution. х — 2у — 2 -5 2x + y + z -2 -2y – z Note: your answers must be fractions (decimals are not allowed).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![(1 point) Solve the linear system below by substitution.
\[
\begin{cases}
x - 2y - z = -5 \\
2x + y + z = -2 \\
-2y - z = 5
\end{cases}
\]
Note: your answers must be fractions (decimals are not allowed).
\( x = \)
\( y = \)
\( z = \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb738ee4b-0d92-438d-b96f-d8d02fb325c0%2F48e22003-0132-427f-bf3b-cd28f45411b2%2Fzpa58ls_processed.png&w=3840&q=75)
Transcribed Image Text:(1 point) Solve the linear system below by substitution.
\[
\begin{cases}
x - 2y - z = -5 \\
2x + y + z = -2 \\
-2y - z = 5
\end{cases}
\]
Note: your answers must be fractions (decimals are not allowed).
\( x = \)
\( y = \)
\( z = \)
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