(1 point) If x is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:(a) n = 5,p = 0.3g2 =O =(b) n = 3, p = 0.5o2 =o =(c) n = 6,p = 0.4O =(d) п %3D 5,р %3 0.5O =

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Answered: (1 point) If X is a binomial random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What is the Variance of a negative binomial random variable with parameters p= 0.35 and r=5? Select one: O a. 26.53 b. 14.29 c. 0.07 O d. 5.151 Next page CS Scanned with CamScanner
Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean ? = 62.0 kg and standard deviation ? = 9.0 kg. Suppose a doe that weighs less than 53 kg is considered undernourished. (c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 70 does should be more than 59 kg. If the average weight is less than 59 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight x for a random sample of 70 does is less than 59 kg (assuming a healthy population)? (Round your answer to four decimal places.) Suppose park rangers captured, weighed, and released 70 does in December, and the average weight was x = 63.8 kg. Do you think the doe population is undernourished or not? Explain. A. Since the sample average is above the mean, it…
If x is a binomial random variable, compute the mean, the standard deviation o, and the variance 2 for each of the following cases: (a) n = = 6, p = 0.1 fl = 0²: % σ= = (b) n = 5, p = 0.2 fl = 0². σ= (c) n = 3, p = 0.8 fl = 0²: 0 = 0² || (d) n = 5, p = 0.6 fl = % 0 =
The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B ( group 2) . A random sample of 16 rats was selected from group land 13 rats from group 2, Then their weight were recorded. The results are shown in the following table n Mean Median sd group 1 16 3.5 3.0 1.05 group 2 13 2.20 2.0 1.15 F15,12,0.05 =0.404 F19,16,0.025 = 0.386| F16,10,0.025 =0.335 F16,10,0.05 =0.401| F15,12,0.1 = 0.496 | F19,16,0.05 =0.451 F10,16,0.025 =0.286 F12,15,0.05 =0.382 F16,19,0.025 =0.371 F10,16,0.05 =0.354 F12,15,0.1=0.475 F16,19,0.05 = 0.437 Construct a 95% confidence interval for the ratio of the variances. [ Hint: because of the rounding select the closest interval ] O a. None of these O b. [ 2.488, 0.238 ] O c. [ 2.160 , 0.309 ] O d. [2.063 , 0.318]
Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1x¯1 = 4.5, s1 = .20, n1 = 15, x⎯⎯2x¯2 = 4.9, s2 = .30, n2 = 15, α = .025, left-tailed test.(Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick" rules for degrees of freedom.) d.f. Not attempted t-calculated Not attempted p-value Not attempted t-critical Not attempted (a-2) Based on the above data choose the correct decision. Do not reject the null hypothesis Reject the null hypothesis
The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B ( group 2) . A random sample of 16 rats was selected from group land 13 rats from group 2, Then their weight were recorded. The results are shown in the following table n Mean Median sd group 1 16 3.5 3.0 1.05 group 2 13 2.20 2.0 1.15 F15,12,0.05 = 0.404 F 19,16,0.025 = 0.386 F16,10,0.025 =0.335| F16,10,0.05 =0.401 F15,12,0.1 =0.496 F19,16,0.05 =0.451 F10,16,0.025 = 0.286 F 12,15,0.05 =0.382 F16,19,0.025 = 0.371| F10,16,0.05 = 0.354 F12,15,0.1 =0.475 F16,19,0.05 = 0.437| Construct a 95% confidence interval for the ratio of the variances. [ Hint: because of the rounding select the closest interval ] O a. None of these O b. [ 2.488, O0.238 ] O c. [ 2.160 , 0.309] O d. [2.063 , 0.318]
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The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 2.5minutes. Assume that the distribution of taxi and takeoff times is approximately normal. You may assume that the jets are lined up on a runway so that one taxies and takes off immediately after the other, and that they take off one at a time on a given runway. (a) What is the probability that for 36 jets on a given runway, total taxi and takeoff time will be less than 320 minutes? (Round your answer to four decimal places.)(b) What is the probability that for 36 jets on a given runway, total taxi and takeoff time will be more than 275 minutes? (Round your answer to four decimal places.)(c) What is the probability that for 36 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes? (Round your answer to four decimal places.)
Find the mean and standard deviation for each binomial random variable: a. n = 60, ππ = .65 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean: Standard Deviation: b. n = 98, ππ = .45 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean: Standard Deviation: ππ c. n = 50, = .70 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean: Standard Deviation:
The mean height of 15-year-old boys (in em) is 175 and the variance is 64. For girls, the mean is 165 and the variance is 64. Assuming that the two populations are nomally distributed. If eight boys and eight girls were sampled, then the probability that the mean height of the sample of boys would be higher than the mean height of the sample of girls 18: O 0 9878 O 0.0062 O 0.9938 0 9972 Let E[X(Y-1)] 10, E[X(Y#1)] 20, V(X) Then E(Y) 8. V(Y) 12 and V(X+Y) 30. O 14/5 12/5 2

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(1 point) If X is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases: (a) n = 5,p = 0.3 o2 = O = (b) п %3D 3,р %3D0.5 = 11 o2 = O = (c) n = 6,p = 0.4 = 11 o2 = (d) n = 5, p = 0.5 o2 = O =