(1 of 2 parts) Suppose you have the following function that is passed the head and tail pointers of a doubly linked list of integers, along with another integer, f. * bool expecto (Node ✶ h, Node *t, int f) { if (h == nullptr || t == h->prev) return false; Node *c = h; Node * r = t; while (c != r) { c = c->next; if (c != r) } r = r->prev; if (c->value return true; f) else if (c->value < f) else return expecto (h, c->prev, f); return expecto (c->next, t, f); if (c->value == f) return true;B else if (c->value < f) else return expecto (h, c->prev, f); return expecto (c->next, t, f); In brief, discuss what this function is doing and discuss its Big-O. Are there any constraints on the values in the linked list?
(1 of 2 parts) Suppose you have the following function that is passed the head and tail pointers of a doubly linked list of integers, along with another integer, f. * bool expecto (Node ✶ h, Node *t, int f) { if (h == nullptr || t == h->prev) return false; Node *c = h; Node * r = t; while (c != r) { c = c->next; if (c != r) } r = r->prev; if (c->value return true; f) else if (c->value < f) else return expecto (h, c->prev, f); return expecto (c->next, t, f); if (c->value == f) return true;B else if (c->value < f) else return expecto (h, c->prev, f); return expecto (c->next, t, f); In brief, discuss what this function is doing and discuss its Big-O. Are there any constraints on the values in the linked list?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:(1 of 2 parts) Suppose you have the following function that is passed the head
and tail pointers of a doubly linked list of integers, along with another integer, f.
*
bool expecto (Node ✶ h, Node *t, int f) {
if (h == nullptr || t == h->prev)
return false;
Node *c = h;
Node * r = t;
while (c != r) {
c = c->next;
if (c != r)
}
r = r->prev;
if (c->value
return true;
f)
else if (c->value < f)
else
return expecto (h, c->prev, f);
return expecto (c->next, t, f);

Transcribed Image Text:if (c->value == f)
return true;B
else if (c->value < f)
else
return expecto (h, c->prev, f);
return expecto (c->next, t, f);
In brief, discuss what this function is doing and discuss its Big-O. Are there any
constraints on the values in the linked list?
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