1) Let x[n] = 8[n] + 28[n – 1] – 8[n – 3] and h[n] = 28[n + 1] + 28[n – 1]. Compute and plot each of the following convolutions using graphical illustration. a) yı[n] = x[n] * h[n] b) y2[n] = x[n + 2] * h[n] c) y3[n] = x[n] * h[n + 2] 2) Consider an input rlnl and a unit impulse response hlnl given by
1) Let x[n] = 8[n] + 28[n – 1] – 8[n – 3] and h[n] = 28[n + 1] + 28[n – 1]. Compute and plot each of the following convolutions using graphical illustration. a) yı[n] = x[n] * h[n] b) y2[n] = x[n + 2] * h[n] c) y3[n] = x[n] * h[n + 2] 2) Consider an input rlnl and a unit impulse response hlnl given by
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you solve 1st, 2nd, and 3rd questions please

Transcribed Image Text:3) Determine and sketch the convolution of the following two signals both analytically and graphical
method:
{
t + 1,
2 - t,
0 <t<1
1<t< 2
x(t)
%3|
0,
elsewhere
h(t) = 8(t + 2) + 28(t + 1)
4) Compute and sketch the output y(t) of the continuous-time LTI system with impulse response
h(t) = e1-tu(t – 1) for an input signal x(t) = u(t) – u(t – 3). Both analytically and graphical
method
![1) Let x[n] = 8[n] + 28[n – 1] – 8[n – 3] and h[n] =
each of the following convolutions using graphical illustration.
a) yı[n] = x[n] * h[n]
b) y2[n] = x[n + 2] * h[n]
с) Уз[п] 3 x[] * h[n + 2]
2) Consider an input x[n] and a unit impulse response h[n] given by
28[n + 1] + 28[n – 1]. Compute and plot
-
%3D
х[п] %3D (1/2)(п-2u(n — 2]
hln] %3D и(n + 2]
Determine and plot the output y[n] = x[n] * h[n]. Both analytically and graphical method](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F950aae86-9012-4518-b045-68fbf0d4af20%2F31cc2991-e349-4867-a46e-c3d6cac93ed5%2F5efkz2d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1) Let x[n] = 8[n] + 28[n – 1] – 8[n – 3] and h[n] =
each of the following convolutions using graphical illustration.
a) yı[n] = x[n] * h[n]
b) y2[n] = x[n + 2] * h[n]
с) Уз[п] 3 x[] * h[n + 2]
2) Consider an input x[n] and a unit impulse response h[n] given by
28[n + 1] + 28[n – 1]. Compute and plot
-
%3D
х[п] %3D (1/2)(п-2u(n — 2]
hln] %3D и(n + 2]
Determine and plot the output y[n] = x[n] * h[n]. Both analytically and graphical method
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