1) Jump and Jump and Link instructions have a six-bit op-code and a 26-bit jump address field. How is the full 32-bit Jump Address calculated? The jump address field is sign-extended six bits to the left. The leftmost four bits of the PC are concatenated with the jump address field, and two bits of zero are concatenated to the end of that. The leftmost six bits of the PC are concatenated with the jump address field. The jump address is ANDed with Register 0 to produce the jump address. -------------------------------------------------------------------------------- 2) How is a branch target address calculated? Sign-extend bits 15:0 of the instruction, append two bits of zeros, and add the result to the PC. Zero extend bits 15:0 of the instruction, append two bits of ones, and subtract the result from the PC. Add the immediate operand to register zero, and sign extend the result. Concatenate the leftmost 16 bits of the PC with the rightmost 16 bits of the instruction. -------------------------------------------------------------------------------- 3)How is the effective address calculated for lw and sw instructions? By converting the byte address to a word address and adding it to the PC. By putting the immediate operand into register 0. By sign-extending bits 15:0 of the instruction, and adding that to the contents of the register whose number is in bits 25:21 of the instruction. By using the shamt field of the instruction to determine where to branch.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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1) Jump and Jump and Link instructions have a six-bit op-code and a 26-bit jump address field. How is the full 32-bit Jump Address calculated?

The jump address field is sign-extended six bits to the left.
The leftmost four bits of the PC are concatenated with the jump address field, and two bits of zero are concatenated to the end of that.
The leftmost six bits of the PC are concatenated with the jump address field.
The jump address is ANDed with Register 0 to produce the jump address.

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2) How is a branch target address calculated?

Sign-extend bits 15:0 of the instruction, append two bits of zeros, and add the result to the PC.
Zero extend bits 15:0 of the instruction, append two bits of ones, and subtract the result from the PC.
Add the immediate operand to register zero, and sign extend the result.
Concatenate the leftmost 16 bits of the PC with the rightmost 16 bits of the instruction.

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3)How is the effective address calculated for lw and sw instructions?

By converting the byte address to a word address and adding it to the PC.
By putting the immediate operand into register 0.
By sign-extending bits 15:0 of the instruction, and adding that to the contents of the register whose number is in bits 25:21 of the instruction.
By using the shamt field of the instruction to determine where to branch.

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