1 JA pump is used to circulate a water from lower Tank to upper tank. The height difference between thefree surface of the two tank is 5 m and the total head losses in the pipe is 5 m.Calculate the brake horsepower of the pump for a water flow rate 6000 l/min. Take the efficiency of thepump is equal to 75% and the density of water 1000 kg/m3

Answered: 1 J A pump is used to circulate a water…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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1 J
A pump is used to circulate a water from lower Tank to upper tank. The height difference between the
free surface of the two tank is 5 m and the total head losses in the pipe is 5 m.
Calculate the brake horsepower of the pump for a water flow rate 6000 l/min. Take the efficiency of the
pump is equal to 75% and the density of water 1000 kg/m3

Expert Solution

Step 1

Given data:

The height difference between the free surface is $h = 5 m$

The total head losses in the pipe is $h_{l} = 5 m$

The discharge flow rate of the water is $Q = 6000 \frac{l}{m i n} = 0.1 \frac{m^{3}}{s}$

The density of the water is $ρ = 1000 \frac{k g}{m^{3}}$

The efficiency of the pump is $η = 75 %$

Step 2

The total head between the tank is as follows:
$H = h + h_{l} H = 5 + 5 H = 10 m$

The water power of the pump is as follows:

$P_{W} = ρ Q g h P_{W} = 1000 \times 0.1 \times 9.81 \times 10 P_{W} = 9810 W$

The brake horsepower of the pump is as follows:

$\begin{array}{rcl} η & = & \frac{P_{W}}{P_{B}} \\ 0.75 & = & \frac{9810}{P_{B}} \\ P_{B} & = & 13080 W H e r e, 1 h p = 746 W \\ P_{B} & = & 17.533 h p \end{array}$

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