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(1) In a hypothesis test of Ho a = 0.05, we conclude: a). Reject Ho c). Reject Ha = 18 vs Ha> 18, we obtain a p-value of 0.016. Using b). Do not reject Ho d). Do not reject Ha μ (2) In a hypothesis test of Ho = 18 vs H₁ > 18, we obtain a p-value of 0.016. Using a = 0.05, we conclude: a). There is evidence that u = 18 b). There is evidence that > 18 c). There is no evidence of anything.

(1) In a hypothesis test of Ho a = 0.05, we conclude: a). Reject Ho c). Reject Ha = 18 vs Ha> 18, we obtain a p-value of 0.016. Using b). Do not reject Ho d). Do not reject Ha μ (2) In a hypothesis test of Ho = 18 vs H₁ > 18, we obtain a p-value of 0.016. Using a = 0.05, we conclude: a). There is evidence that u = 18 b). There is evidence that > 18 c). There is no evidence of anything.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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(1) In a hypothesis test of Ho μ = 18 vs Ha> 18, we obtain a p-value of 0.016. Using a = 0.05, we conclude: a). Reject Ho c). Reject Ha b). Do not reject Ho d). Do not reject Ha (2) In a hypothesis test of Ho a = 0.05, we conclude: μ = 18 vs Hau > 18, we obtain a p-value of 0.016. Using a). There is evidence that = 18 b). There is evidence that > 18 c). There is no evidence of anything.
Transcribed Image Text:(1) In a hypothesis test of Ho μ = 18 vs Ha> 18, we obtain a p-value of 0.016. Using a = 0.05, we conclude: a). Reject Ho c). Reject Ha b). Do not reject Ho d). Do not reject Ha (2) In a hypothesis test of Ho a = 0.05, we conclude: μ = 18 vs Hau > 18, we obtain a p-value of 0.016. Using a). There is evidence that = 18 b). There is evidence that > 18 c). There is no evidence of anything.
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