1) If 493 kcal is added to a gas that expands and does 674 kJ of work, what is the change in the internal energy of the gas? kJ Submit You currently have 0 submissions for this question. Only 10 submission are allowed.
1) If 493 kcal is added to a gas that expands and does 674 kJ of work, what is the change in the internal energy of the gas? kJ Submit You currently have 0 submissions for this question. Only 10 submission are allowed.
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![**Thermodynamics Question**
**Problem Statement:**
1) If 493 kcal is added to a gas that expands and does 674 kJ of work, what is the change in the internal energy of the gas?
**Answer Submission Box:**
```
__________ kJ
[Submit Button]
```
**Instructions:**
- You currently have 0 submissions for this question.
- Only 10 submissions are allowed.
- You can make 10 more submissions for this question.
**Explanation:**
In this thermodynamics problem, we are asked to determine the change in the internal energy (ΔU) of a gas when a certain amount of heat is added, and the gas performs work. The problem states:
1. Heat added to the gas (Q) = 493 kcal
2. Work done by the gas (W) = 674 kJ
**Steps:**
1. Convert the heat added from kcal to kJ
- 1 kcal = 4.184 kJ
- Q (in kJ) = 493 kcal * 4.184 kJ/kcal
2. Use the First Law of Thermodynamics, which states:
- ΔU = Q - W
Where
- ΔU is the change in internal energy,
- Q is the heat added to the system, and
- W is the work done by the system.
After performing the calculations, submit your answer in the provided box and press the "Submit" button for evaluation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6e52c04-e2c3-4e2d-83a7-f5740c8e0fd5%2Fea3c651b-973c-44f2-a4ba-3492b518bb50%2F3lj40j5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Thermodynamics Question**
**Problem Statement:**
1) If 493 kcal is added to a gas that expands and does 674 kJ of work, what is the change in the internal energy of the gas?
**Answer Submission Box:**
```
__________ kJ
[Submit Button]
```
**Instructions:**
- You currently have 0 submissions for this question.
- Only 10 submissions are allowed.
- You can make 10 more submissions for this question.
**Explanation:**
In this thermodynamics problem, we are asked to determine the change in the internal energy (ΔU) of a gas when a certain amount of heat is added, and the gas performs work. The problem states:
1. Heat added to the gas (Q) = 493 kcal
2. Work done by the gas (W) = 674 kJ
**Steps:**
1. Convert the heat added from kcal to kJ
- 1 kcal = 4.184 kJ
- Q (in kJ) = 493 kcal * 4.184 kJ/kcal
2. Use the First Law of Thermodynamics, which states:
- ΔU = Q - W
Where
- ΔU is the change in internal energy,
- Q is the heat added to the system, and
- W is the work done by the system.
After performing the calculations, submit your answer in the provided box and press the "Submit" button for evaluation.
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