1 g(x): %D х2 — 2 f(x) = VIx| – 2 %3D - 1 1 g(f(x)) = |x| – 4 2 |x|– 2 – 2 (Vix| – 2) – 2 - - Dom g(f (x)) = {x € dom f | f (x) e dom g} = {x € (-0, –2] U [2, 0) | Vīx| – 2 € (-0,-v2) U (-V2, v2) u
1 g(x): %D х2 — 2 f(x) = VIx| – 2 %3D - 1 1 g(f(x)) = |x| – 4 2 |x|– 2 – 2 (Vix| – 2) – 2 - - Dom g(f (x)) = {x € dom f | f (x) e dom g} = {x € (-0, –2] U [2, 0) | Vīx| – 2 € (-0,-v2) U (-V2, v2) u
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter8: Introduction To Functions
Section8.8: Linear And Quadratic Functions
Problem 4ST
Related questions
Question
![1
g(x)
%|
x2
- 2
f (x) = Vlx| – 2
1
1
1
g(f(x)) =
(/i#I – 2)´ – 2
|x|– 2 – 2
|x| – 4
-
Dom g(f (x)) = {x € dom f | f (x) E dom g}
= {x € (-00, -2] U [2, 0) | Vīx| – 2 € (-∞, –v2) u (-v2, V2) u ( v2, co0)}
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa12f3d2a-f58e-4210-9349-b2715c001625%2F2712fb89-6d81-4102-a101-3472df04a38e%2Fplzz8hs_processed.png&w=3840&q=75)
Transcribed Image Text:1
g(x)
%|
x2
- 2
f (x) = Vlx| – 2
1
1
1
g(f(x)) =
(/i#I – 2)´ – 2
|x|– 2 – 2
|x| – 4
-
Dom g(f (x)) = {x € dom f | f (x) E dom g}
= {x € (-00, -2] U [2, 0) | Vīx| – 2 € (-∞, –v2) u (-v2, V2) u ( v2, co0)}
%3D
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