If f(x) = 2×, show that f(x + h) – f(x) = 2×( 2" -1). h Simplify your answers completely at each step. f(x) = 2X, so f(x + h) – f(x) - 2* - - h (2*%( )- 2* h II

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If \( f(x) = 2^x \), show that

\[
\frac{f(x+h) - f(x)}{h} = 2^x \left( \frac{2^h - 1}{h} \right).
\]

Simplify your answers completely at each step.

\( f(x) = 2^x \), so

\[
\frac{f(x+h) - f(x)}{h} = \frac{2^{x+h} - 2^x}{h}
\]

\[
= \frac{(2^x)(2^h) - 2^x}{h}
\]

This expression highlights the process of deriving the limit definition of a derivative for exponential functions. The steps guide the simplification from the difference quotient to a form that demonstrates the factorization of common elements.
Transcribed Image Text:If \( f(x) = 2^x \), show that \[ \frac{f(x+h) - f(x)}{h} = 2^x \left( \frac{2^h - 1}{h} \right). \] Simplify your answers completely at each step. \( f(x) = 2^x \), so \[ \frac{f(x+h) - f(x)}{h} = \frac{2^{x+h} - 2^x}{h} \] \[ = \frac{(2^x)(2^h) - 2^x}{h} \] This expression highlights the process of deriving the limit definition of a derivative for exponential functions. The steps guide the simplification from the difference quotient to a form that demonstrates the factorization of common elements.
**Problem Statement:**

If $5000 is borrowed at a rate of 5.75% interest per year, compounded quarterly, find the amount due at the end of the given number of years. (Round your answers to the nearest cent.)

**Questions:**

(a) 4 years

$ [Input Box] ✖

(b) 6 years

$ [Input Box] ✖

(c) 8 years

$ [Input Box] ✖

**Explanation:**

Given that the principal amount is $5000, with an annual interest rate of 5.75% compounded quarterly, we are asked to calculate the future amount for different periods of time: 4 years, 6 years, and 8 years.

Each option provides a text box for input, which shows an "✖" symbol indicating incorrect or incomplete input. 

To solve, use the compound interest formula:
\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \]
where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount ($5000).
- \( r \) is the annual interest rate (5.75% or 0.0575).
- \( n \) is the number of times that interest is compounded per year (quarterly, so 4).
- \( t \) is the time the money is invested for in years.

Substitute the values for each case to find the required amounts.
Transcribed Image Text:**Problem Statement:** If $5000 is borrowed at a rate of 5.75% interest per year, compounded quarterly, find the amount due at the end of the given number of years. (Round your answers to the nearest cent.) **Questions:** (a) 4 years $ [Input Box] ✖ (b) 6 years $ [Input Box] ✖ (c) 8 years $ [Input Box] ✖ **Explanation:** Given that the principal amount is $5000, with an annual interest rate of 5.75% compounded quarterly, we are asked to calculate the future amount for different periods of time: 4 years, 6 years, and 8 years. Each option provides a text box for input, which shows an "✖" symbol indicating incorrect or incomplete input. To solve, use the compound interest formula: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount ($5000). - \( r \) is the annual interest rate (5.75% or 0.0575). - \( n \) is the number of times that interest is compounded per year (quarterly, so 4). - \( t \) is the time the money is invested for in years. Substitute the values for each case to find the required amounts.
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