Answered: 1) Find the expected value (mean) and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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x	P(X=x)
10	0.42
15	0.33
17	0.10
25	0.15

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Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 3 4 5 Probability 0.259 0.293 0.244 0.150 0.037 0.017 ... (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is (Round to one decimal place as needed.) The variance is (Round to one decimal place as needed.) The standard deviation is (Round to one decimal place as needed.) (b) Interpret the results. The mean is , so the average batch of 1000 machine parts has The standard deviation is so the typical number of defects in a batch of 1000 (Round to one decimal place as needed.)
Suppose you were given this Joint Probability Distribution: y = number of times city name is stated 1 Find the conditional mean and variance of Y|3 Mean = Blank 1 Variance = Blank 2 x = number of bars of signal strength 2 3 4 0.15 0.1 0.05 3 0.02 0.1 0.05 20.02 0.03 0.2 1 0.01 0.02 0.25 0.2 0.25 0.55 Marginal probability distribution of X Marginal probability distribution of Y 0.3 0.17 0.25 0.28
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Consider the distribution table below x 5 10 15 20 P ( X = x ) 0.5 0.2 0.2 0.2 Then Answer options: The standard deviation of X is 5.025 The variance of X is 25.25 The expected value of X is 11.5 None of the choices, the table cannot be a probability distribution table.
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Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 4 Probability 0.262 0.299 0.233 0.153 0.037 0.016 ... (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is 1.5. (Round to one decimal place as needed.) The variance is (Round to one decimal place as needed.)
2. Two businessmen examine the joint distribution for X and Y. Find the Expected value of X, Y, and XY, variances of X, Y, and XY, and standard deviation of X and Y. y f(x,y) 1 2 3 0.10 0.05 0.02 x 0.10 0.35 0.05 0.03 0.10 0.20 123
Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 0 1 2 3 Probability 0.269 0.295 0.241 0.144 The variance is 1.5. (Round to one decimal place as needed.) (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is 1.4. (Round to one decimal place as needed.) The standard deviation is 1.2 (Round to one decimal place as needed.) (b) Interpret the results. 4 0.038 The mean is so the average batch of 1000 machine parts has the typical number of defects in a batch of 1000 (Round to one decimal place as needed.) 5 0.013 0 The standard deviation is SO
Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 4 Probability 0.264 0.289 0.238 0.156 0.037 0.016 ... (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is 1.5. (Round to one decimal place as needed.) The variance is (Round to one decimal place as needed.)

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1) Find the expected value (mean) and the variance for the following distribution. Probability Distribution x P(X=x) 10 0.42 15 0.33 17 0.10 25 0.15