**Transcript for Educational Website:**In Part 1, complete the structures and draw the mechanism arrows for the following reaction. In Part 2, select all the byproducts that are formed.---**Part 1**Please draw all four bonds at stereocenters. Do not use wedges and dashes on sp² carbons.![Diagram of chemical structure with a curved arrow](#)- Draw the missing curved arrow notation.A diagram is presented showing a chemical structure. The left structure features a bromine (Br) atom attached to a carbon chain with a phenyl group. A curved arrow is shown to guide the user in drawing the mechanism.---**Part 2**Select all byproducts of the reaction. **Choose one or more:**- [ ] A. H₂O- [ ] B. HBr- [ ] C. Br⁻- [ ] D. (CH₃)₂COH---**Diagram Explanation:**The diagram illustrates a chemical reaction mechanism. In the image:- An initial molecule is depicted with specified stereochemistry.- The product of the reaction is shown, and users are prompted to complete the reaction by drawing the curved arrow to indicate the movement of electrons.- Part 2 provides multiple-choice options for selecting the potential byproducts of the reaction.

In elimination reaction, an alkene is formed.Write the reaction. Here, tert-butyl oxide acts as a base and abstracts a proton forming a double bond and eliminating Br. Part 2. The byproduct formed are (CH3)3COH and Br-. Hence the correct answer is c and d.