(1) derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) (2) use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Specify the values for key points on the diagrams. Let a = 10.6 ft, b = 7.1 ft, w, = 2.2 kips/ft, and w = 10.5 kips/ft. Derive the equations and construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Part 1 Part 2 Part 3 Part 4 a Incorrect. Review Examples 7.1-7.5. In this case, the maximum bending moment occurs at a location where the shear force VVis equal to zero. If the correct shear force diagram is constructed, it can be seen that the shear force equals zero at anxx-value on the intervala ≤ x < a + ba ≤ x

Structural Analysis
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Chapter2: Loads On Structures
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For the beam shown:

1. Derive equations for the shear force \( V \) and the bending moment \( M \) for any location in the beam. (Place the origin at point \( A \)).
2. Use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Specify the values for key points on the diagrams.

Let \( a = 10.6 \, \text{ft} \), \( b = 7.1 \, \text{ft} \), \( w_a = 2.2 \, \text{kips/ft} \), and \( w_b = 10.5 \, \text{kips/ft} \). Derive the equations and construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.

*Diagram:*
A beam is shown with a span divided into two sections: \( A \) to \( B \) of length \( a \) and \( B \) to \( C \) of length \( b \). The beam is subjected to distributed loads \( w_a \) and \( w_b \).

### Parts:

**Part 1**

**Part 2**

**Part 3**

**Part 4**

Incorrect: Review Examples 7-1–7-5. In this case, the maximum bending moment occurs at a location where the shear force \( V \) is equal to zero. If the correct shear force diagram is constructed, it can be seen that the shear force equals zero at an \( x \)-value on the interval \( a \leq x < a + b \).

Consider the entire beam and use your shear-force and bending-moment diagrams to determine the bending moment with the largest absolute value, \( M_{\text{max}} \), and its location, \( x_{\text{max}} \). Use the bending-moment sign convention detailed in Section 7.2. If the bending moment with the largest absolute value is positive, enter a positive value for \( M_{\text{max}} \), or if it’s negative, enter a negative value.

\( M_{\text{max}} = \) 1.00E3 kip-ft

\( x_{\text{max}} = \) 8.30 ft
Transcribed Image Text:For the beam shown: 1. Derive equations for the shear force \( V \) and the bending moment \( M \) for any location in the beam. (Place the origin at point \( A \)). 2. Use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Specify the values for key points on the diagrams. Let \( a = 10.6 \, \text{ft} \), \( b = 7.1 \, \text{ft} \), \( w_a = 2.2 \, \text{kips/ft} \), and \( w_b = 10.5 \, \text{kips/ft} \). Derive the equations and construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. *Diagram:* A beam is shown with a span divided into two sections: \( A \) to \( B \) of length \( a \) and \( B \) to \( C \) of length \( b \). The beam is subjected to distributed loads \( w_a \) and \( w_b \). ### Parts: **Part 1** **Part 2** **Part 3** **Part 4** Incorrect: Review Examples 7-1–7-5. In this case, the maximum bending moment occurs at a location where the shear force \( V \) is equal to zero. If the correct shear force diagram is constructed, it can be seen that the shear force equals zero at an \( x \)-value on the interval \( a \leq x < a + b \). Consider the entire beam and use your shear-force and bending-moment diagrams to determine the bending moment with the largest absolute value, \( M_{\text{max}} \), and its location, \( x_{\text{max}} \). Use the bending-moment sign convention detailed in Section 7.2. If the bending moment with the largest absolute value is positive, enter a positive value for \( M_{\text{max}} \), or if it’s negative, enter a negative value. \( M_{\text{max}} = \) 1.00E3 kip-ft \( x_{\text{max}} = \) 8.30 ft
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