1) Complete the following reaction and provide a detailed, step-by-step mechanism for the process. HBr 2) Provide the structure of the major organic product in the reactions below. o - HI CH3 man H₂C. CH3 CH₂CH3 на H₂C CH3 HBr

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### Organic Chemistry Reactions and Mechanisms

Welcome to the Organic Chemistry section. Below, you'll find detailed reactions and step-by-step mechanisms for the provided chemical processes.

---

#### 1. Hydrogen Bromide Addition to an Alkene

**Reaction Description:**

Complete the following reaction and provide a detailed, step-by-step mechanism for the process.

**Reactants:**
- Alkene: CH₃-CH=CH₂
- Hydrogen Bromide (HBr)

**Mechanism Steps:**

1. **Protonation of the Alkene:**
   - The π electrons of the double bond react with the proton (H⁺) from HBr, forming a carbocation intermediate and a bromide ion (Br⁻).
   - The most stable carbocation intermediate will form. For this reaction:
     \[
     CH₃-CH=CH₂ + HBr \rightarrow CH₃-CH⁺-CH₃ + Br⁻
     \]
   - The positive charge resides on the carbon that was initially double-bonded.

2. **Nucleophilic Attack:**
   - The bromide ion (Br⁻) attacks the carbocation, forming the final product.
   - The final product is 2-bromopropane:
     \[
     CH₃-CH⁺-CH₃ + Br⁻ \rightarrow CH₃-CHBr-CH₃
     \]

---

#### 2. Structure of Major Organic Products from the Reactions

Provide the structure of the major organic product in the reactions below.

**a. Reaction with HI**

**Reactant:**
- Cyclohexene (contains a six-membered ring with one double bond)

**Product:**
- Cyclohexyl iodide

**Mechanism:**
- The π electrons of the double bond react with hydrogen iodide (HI) in a similar fashion to the HBr reaction above. The iodine anion (I⁻) attaches to the most stable carbocation intermediate.

**b. Reaction with HBr**

**Reactant:**
- An alkene with a long carbon chain and one double bond.

**Product:**
- The major product will follow Markovnikov's rule, where the bromine (Br⁻) attaches to the carbon that is most stable (the more substituted carbon).

**c. Reaction with HCl**

**Reactant:**
- 2-but
Transcribed Image Text:### Organic Chemistry Reactions and Mechanisms Welcome to the Organic Chemistry section. Below, you'll find detailed reactions and step-by-step mechanisms for the provided chemical processes. --- #### 1. Hydrogen Bromide Addition to an Alkene **Reaction Description:** Complete the following reaction and provide a detailed, step-by-step mechanism for the process. **Reactants:** - Alkene: CH₃-CH=CH₂ - Hydrogen Bromide (HBr) **Mechanism Steps:** 1. **Protonation of the Alkene:** - The π electrons of the double bond react with the proton (H⁺) from HBr, forming a carbocation intermediate and a bromide ion (Br⁻). - The most stable carbocation intermediate will form. For this reaction: \[ CH₃-CH=CH₂ + HBr \rightarrow CH₃-CH⁺-CH₃ + Br⁻ \] - The positive charge resides on the carbon that was initially double-bonded. 2. **Nucleophilic Attack:** - The bromide ion (Br⁻) attacks the carbocation, forming the final product. - The final product is 2-bromopropane: \[ CH₃-CH⁺-CH₃ + Br⁻ \rightarrow CH₃-CHBr-CH₃ \] --- #### 2. Structure of Major Organic Products from the Reactions Provide the structure of the major organic product in the reactions below. **a. Reaction with HI** **Reactant:** - Cyclohexene (contains a six-membered ring with one double bond) **Product:** - Cyclohexyl iodide **Mechanism:** - The π electrons of the double bond react with hydrogen iodide (HI) in a similar fashion to the HBr reaction above. The iodine anion (I⁻) attaches to the most stable carbocation intermediate. **b. Reaction with HBr** **Reactant:** - An alkene with a long carbon chain and one double bond. **Product:** - The major product will follow Markovnikov's rule, where the bromine (Br⁻) attaches to the carbon that is most stable (the more substituted carbon). **c. Reaction with HCl** **Reactant:** - 2-but
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