(1-) – Bzy = ax (1 K Y = yxy – dy where a, B, y, and d are positive constants. Assume that K >. The K is locally asymptotically stable. equilibrium ye = True False

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The population of prey is denoted æ(t) (in millions) and the population
of predators is denoted y(t) (in millions). We assume that:
• In the absence of predators, the prey population satisfies the logistic
growth model with a carrying capacity K (in millions).
• In the absence of prey, the predator population decays at a rate
proportional to the predator population.
• The prey population decays at a rate proportional to the product of
prey and predators.
• The predator population grows at a rate proportional to the product
of prey and predators.
These assumptions lead to the following nonlinear system of differential
equations:
(1-*) – Bay
a' :
= ax
K
y = yxy – Sy
where a, B, y, and d are positive constants. Assume that K > . The
K
is locally asymptotically stable.
equilibrium ye =
True
False
Transcribed Image Text:The population of prey is denoted æ(t) (in millions) and the population of predators is denoted y(t) (in millions). We assume that: • In the absence of predators, the prey population satisfies the logistic growth model with a carrying capacity K (in millions). • In the absence of prey, the predator population decays at a rate proportional to the predator population. • The prey population decays at a rate proportional to the product of prey and predators. • The predator population grows at a rate proportional to the product of prey and predators. These assumptions lead to the following nonlinear system of differential equations: (1-*) – Bay a' : = ax K y = yxy – Sy where a, B, y, and d are positive constants. Assume that K > . The K is locally asymptotically stable. equilibrium ye = True False
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