- 1 attachment Determine the acceleration of each body and the tension in the cord supporting block A. Coeff friction is 0.20.
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A: Since we only answer up to three subparts, we will answer first three. Please resubmit the question…
Q: 1000 kg F p = 0.1 10°
A: Given, Mass M = 1000 kg Angle , A = 10° Coefficient of friction, m = 0.1
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A: Mass (m) = 50 g = 0.05 kg displacement (d) = 7.6 cm = 0.076 m
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A: F= 710 l b ∆PCB 34 + α + 180 -52 = 180 α = 180
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Q: Answers: Fx= Fy= Fn = Ft= i i i 67° 47° B F = 850 lb lb lb lb lb
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A: mass =4 kg angle = 20oF = 35 N a = 2.5 m/s2
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Q: A force of 15N acts on a body of mass 2kg. Calculate the acceleration produced.
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Q: a 7° C = ? &N 11
A:
Use g=9.81 m/s2, g=32.2 ft/s2
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