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1 atm, how much energy is required to heat 61.0 g H,O(s) at -10.0 °C to H,O(g) at 119.0 °C? Use the heat transfer nstants found in this table.

1 atm, how much energy is required to heat 61.0 g H,O(s) at -10.0 °C to H,O(g) at 119.0 °C? Use the heat transfer nstants found in this table.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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At 1 atm, how much energy is required to heat 61.0 g H,O(s) at – 10.0 °C to H,O(g) at 119.0 °C? Use the heat transfer constants found in this table. kJ
Transcribed Image Text:At 1 atm, how much energy is required to heat 61.0 g H,O(s) at – 10.0 °C to H,O(g) at 119.0 °C? Use the heat transfer constants found in this table. kJ
Expert Solution
Step 1

The process is carried in 5 stages 

To heat ice from -10° to 0° C 

 

Q = mc∆T 

     = 61×2.087× 10 

   = 1273.07 J 

2) To melt the ice at 0°C to water at 0°C.

Q = m x Enthalpy of fusion

    = 61 g x 333.6 J/g

    = 20349.6 J

Q = 20349.6 J

3) To heat the water from 0°C to boiling at 100°C

Q = mcdT where c = specific heat of water , dT = 100°C

   = 61 g x 4.184 J/g/°C x 100°C

= 25522.4 J

Q = 25522.4 J

4) To vaporize the water to steam at 100°C
Q = m x Enthalpy of vaporization

    = 61 g x 2257 J/g

    = 137677 J

Q = 137677 J. 

5)

) To heat the steam from 100°C to 119°C

Q = mcdT where c = specific heat of gaseous H2O (steam) , dT = 19°C

   = 61 g x 2.000 J/g/°C x 100°C

= 2318 J

 

 

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