1) As a project, student's construct a mobile representing some of the major food groups. Their completed artwork is shown below. Find the masses m1, m2, m3that are required for a perfectly balanced mobile. Assume that strings and the horizontal rods have negligible mass 18 cm 31 cm 6.0 cm 24 cm 0.30 kg 12 cm 18 cm MILK
Fluid Pressure
The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.
Gauge Pressure
Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem to bother anyone as the bodily fluids are constantly pushing outwards with the same force but if one swims down into the ocean a few feet below the surface one can notice the difference, there is increased pressure on the eardrum, this is due to an increase in hydrostatic pressure.
![### Transcription and Explanation
**Equation:**
\[ x_{cg} = \frac{x_1 m_1 + x_2 m_2}{m_1 + m_2} \]
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**Problem:**
1) As a project, students construct a mobile representing some of the major food groups. Their completed artwork is shown below. Find the masses \(m_1, m_2, m_3\) that are required for a perfectly balanced mobile. Assume that strings and the horizontal rods have negligible mass.
**Diagram Description:**
- A mobile consists of several components suspended from rods.
- A mass of \(0.20 \, \text{kg}\) is located 18 cm from the fulcrum (center point of balance).
- Another mass of \(0.30 \, \text{kg}\) is located 24 cm from a different fulcrum.
- The mobile includes unknown masses \(m_1\), \(m_2\), and \(m_3\) at different points.
- The distances between the masses and their respective points of suspension are labeled: 12 cm, 18 cm, 6 cm, 31 cm.
**Strategy:**
We can find all three unknown masses by repeatedly applying the condition for balance:
\[ m_1 x_1 = m_2 x_2 \]
1. First, apply the balance condition to \(m_1\) and \(m_2\), with the distance \(x_1 = 12 \, \text{cm}\) and \(x_2 = 18 \, \text{cm}\). This provides a relationship between \(m_1\) and \(m_2\).
2. To establish a second relation between \(m_1\) and \(m_2\), apply the balance condition at the next level of the mobile. The mass \((m_1 + m_2)\) at the distance of 6 cm must balance with the mass \(0.30 \, \text{kg}\) located at 24 cm. These conditions help determine \(m_1\) and \(m_2\).
3. To find \(m_3\), apply the balance condition again, this time considering the mass:
\[ (m_1 + m_2 + 0.30 \, \text{kg} + 0.20 \, \text{](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7fd067d-2bd8-42c8-9cf1-a7f2351dbf76%2Fe97dce3f-3dfa-4a31-87d2-cfbacf29d2ec%2Fb8kb6oa_processed.png&w=3840&q=75)
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