1) A tugboat pushes a cruise ship with a force moving the ship along straight ?=1.20?+2.30???,path with a displacement of . Find∆?=381?+462?a. the work done by the tugboat (5 pts)b. the angle between the force and displacement (5pts)2) As shown below, a passenger pulls on the suitcase with a force of 30.0 N and that has a mass ??displaces the suitcase horizontally 10.0 m. The angle between F and the horizontal is 30 . The coefficient °of kinetic friction ??=?.??The force that the passenger applies to the suitcase is not in the same direction as the displacement of the suitcase, so we have to find the “piece” or “component” of the force vector that is in the same ?direction as the displacement. In other words, we must find , where is the angle between ??=??????the two vectors, and ???a.If , what work is done on the suitcase by the passenger? (5 pts)?=30°b. What is the work done on the suitcase by friction? (remember that we can always express the force due to kinetic friction as follows: ; so now that we have the force we can find the ??=???work done by multiplying this force by the displacement. Be careful --- the normal force is NOT mg. (5pts)
1) A tugboat pushes a cruise ship with a force moving the ship along straight ?=1.20?+2.30???,path with a displacement of . Find∆?=381?+462?a. the work done by the tugboat (5 pts)b. the angle between the force and displacement (5pts)2) As shown below, a passenger pulls on the suitcase with a force of 30.0 N and that has a mass ??displaces the suitcase horizontally 10.0 m. The angle between F and the horizontal is 30 . The coefficient °of kinetic friction ??=?.??The force that the passenger applies to the suitcase is not in the same direction as the displacement of the suitcase, so we have to find the “piece” or “component” of the force vector that is in the same ?direction as the displacement. In other words, we must find , where is the angle between ??=??????the two vectors, and ???a.If , what work is done on the suitcase by the passenger? (5 pts)?=30°b. What is the work done on the suitcase by friction? (remember that we can always express the force due to kinetic friction as follows: ; so now that we have the force we can find the ??=???work done by multiplying this force by the displacement. Be careful --- the normal force is NOT mg. (5pts)
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