(1) A sailboat is sailing at a bearing of 35° North of East, while the wind is exerting a force of 750 Newtons to the North on the sails. How much work does the wind do while the sailboat travels 4 kilometers? Hint: draw the vectors and note that Ois the angle between the vectors when you put their tails together.

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Certainly! Here's a transcription and explanation for the educational website:

---

**Physics Application: Work Done by the Wind on a Sailboat**

**Problem 1:**
A sailboat is sailing at a bearing of 35° North of East, while the wind is exerting a force of 750 Newtons to the North on the sails. How much work does the wind do while the sailboat travels 4 kilometers? 

*Hint:* Draw the vectors and note that \( \theta \) is the angle between the vectors when you put their tails together.

**Vector Calculations in Three Dimensions:**
For three-dimensional vectors \(\vec{A} = A_x\hat{i} + A_y\hat{j} + A_z\hat{k}\) and \(\vec{B} = B_x\hat{i} + B_y\hat{j} + B_z\hat{k}\), the scalar product written in terms of components will be:

\[
\vec{A} \cdot \vec{B} = A_x B_x + A_y B_y + A_z B_z
\]

This provides two methods to calculate the scalar product:

1. Using the magnitude of the vectors and the angle between the vectors.
2. Using the components of the vectors.

We choose whichever method is easier for the particular problem.

---

To solve the problem, consider drawing the vectors representing the sailboat's direction and the wind's force. Determining the angle between these vectors will allow you to calculate the work done using the equation for work:

\[ 
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) 
\]

where:
- Force is 750 N,
- Distance is 4 km, and
- \( \theta \) is the angle between the sailboat's direction and the wind's direction.

Use the provided methods to find the most straightforward solution to the problem.
Transcribed Image Text:Certainly! Here's a transcription and explanation for the educational website: --- **Physics Application: Work Done by the Wind on a Sailboat** **Problem 1:** A sailboat is sailing at a bearing of 35° North of East, while the wind is exerting a force of 750 Newtons to the North on the sails. How much work does the wind do while the sailboat travels 4 kilometers? *Hint:* Draw the vectors and note that \( \theta \) is the angle between the vectors when you put their tails together. **Vector Calculations in Three Dimensions:** For three-dimensional vectors \(\vec{A} = A_x\hat{i} + A_y\hat{j} + A_z\hat{k}\) and \(\vec{B} = B_x\hat{i} + B_y\hat{j} + B_z\hat{k}\), the scalar product written in terms of components will be: \[ \vec{A} \cdot \vec{B} = A_x B_x + A_y B_y + A_z B_z \] This provides two methods to calculate the scalar product: 1. Using the magnitude of the vectors and the angle between the vectors. 2. Using the components of the vectors. We choose whichever method is easier for the particular problem. --- To solve the problem, consider drawing the vectors representing the sailboat's direction and the wind's force. Determining the angle between these vectors will allow you to calculate the work done using the equation for work: \[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \] where: - Force is 750 N, - Distance is 4 km, and - \( \theta \) is the angle between the sailboat's direction and the wind's direction. Use the provided methods to find the most straightforward solution to the problem.
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