1- A rigid tank which acts as a perfect heat insulator and which has a negligible heat capacity is divided into two unequal parts A and B by a partition. Different amounts of the same ideal gas are contained in the two parts of the tank. The initial conditions of temperature T, pressure P, and total volume V are known for both parts of the tank. Find expressions for the equilibrium temperature T and pressure P reached after removal of the partition. Assume that C, the molar heat capacity of the gas, is constant and that the process is adiabatic.
1- A rigid tank which acts as a perfect heat insulator and which has a negligible heat capacity is divided into two unequal parts A and B by a partition. Different amounts of the same ideal gas are contained in the two parts of the tank. The initial conditions of temperature T, pressure P, and total volume V are known for both parts of the tank. Find expressions for the equilibrium temperature T and pressure P reached after removal of the partition. Assume that C, the molar heat capacity of the gas, is constant and that the process is adiabatic.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:1- A rigid tank which acts as a perfect heat insulator and which has a negligible heat capacity
is divided into two unequal parts A and B by a partition. Different amounts of the same ideal
gas are contained in the two parts of the tank. The initial conditions of temperature T, pressure
P, and total volume V are known for both parts of the tank. Find expressions for the equilibrium
temperature T and pressure P reached after removal of the partition. Assume that C, the molar
heat capacity of the gas, is constant and that the process is adiabatic.
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