You have compressed liquid propane in a 5 ft³ closed rigid vessel at 6000 psia and 300 °F but for safety reasons you had to cool the system to lower the pressure to 100 psia. However, this resulted in a two-phase system. Using the information below determine the properties required in the Table: Results Computed. Show all your work and write your answers in the cells provided. Table: Given Data T₁ (F) 300 T₂ (F) 55 Tabley P₁(psia) 6000 P2 (psia) 100 Pg1 (lbm/ft³) 28.262 Pg2 (lbm/ft³) 0.93089 Ug₁(Btu/Ibm) 225.95 P12(lbm/ft3) 31.878 Ug2(Btu/Ibm) 233.36 J U₁2(Btu/lbm) 99.564

You have compressed liquid propane in a 5 ft³ closed rigid vessel at 6000 psia and 300 °F but for safety reasons you had to cool the system to lower the pressure to 100 psia. However, this resulted in a two-phase system. Using the information below determine the properties required in the Table: Results Computed. Show all your work and write your answers in the cells provided. Table: Given Data T₁ (F) 300 T₂ (F) 55 Tabley P₁(psia) 6000 P2 (psia) 100 Pg1 (lbm/ft³) 28.262 Pg2 (lbm/ft³) 0.93089 Ug₁(Btu/Ibm) 225.95 P12(lbm/ft3) 31.878 Ug2(Btu/Ibm) 233.36 J U₁2(Btu/lbm) 99.564

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Work and Heat Transfer

It is generally related to thermal engineering which tells about the use, creation, conversion and transfer of heat energy between the systems. It is also considered that to transfer heat from one source to another, transfer of masses is also required. There are various mechanisms by which, transfer of heat takes place i.e. thermal conduction, convection, radiation or by change of phase. All these mechanisms have their own specific features which sometimes occur simultaneously within the same system.

Question

Problem 4.
You have compressed liquid propane in a 5 ft³ closed rigid vessel at 6000 psia and 300 °F but for
safety reasons you had to cool the system to lower the pressure to 100 psia. However, this resulted in
a two-phase system.
Using the information below determine the properties required in the Table: Results Computed.
Show all your work and write your answers in the cells provided.
Table: Given Data
T₁ (F)
300
T₂ (F)
55
P₁(psia)
6000
P2 (psia)
100
Pg1 (lbm/ft³)
28.262
Pg2 (1bm/ft³)
0.93089
Table: Results Computed (end '2')
Ug₁(Btu/lbm)
225.95
P12(lbm/ft3)
31.878
Ug2(Btu/Ibm)
233.36
J
U₁2(Btu/lbm)
99.564
OC

Total Mass of propane
Mass of Liquid
Volume of Gas
U₂ (BTU)
Q (BTU)
=
=
=
€

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Step 1: Total Mass of propane

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Step 2: Mass of liquid

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Step 3: Volume of gas

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Step 4: Internal energy of the gas in the two-phase system:

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Step 5: Heat added or removed (Q) in this process (BTU)

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