(1 3 3 18. The inverse of the matrix A=|1 4 3 is 1 3 4 7 -3 -3 -1 1 0 |. What is the solution of -1 0 1 x+3y+3z=14 the system of equations x+4y+3z=16 ? x+3y+4z=17 3 A. y = 2 1 y 2 -3 С. y = 2 3 D. y = 2 -3 10 Lat II B.
(1 3 3 18. The inverse of the matrix A=|1 4 3 is 1 3 4 7 -3 -3 -1 1 0 |. What is the solution of -1 0 1 x+3y+3z=14 the system of equations x+4y+3z=16 ? x+3y+4z=17 3 A. y = 2 1 y 2 -3 С. y = 2 3 D. y = 2 -3 10 Lat II B.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:1 3
2(0
20. Given that
4
then the
3
18. The inverse of the matrix A=1 4 3 is
3 x -3
-6 -2
1 3 4
value of x is:
А. —9
В. -4
С. -3
7
-3 -3
1
What is the solution of
-1
1
D. -2
x+3y+3z =14
the system of equations x+4y+3z=16?
x+3y+4z =17
21. If matrix A is a 2x3matrix, it can be multiplied
by matrix B to obtain AB only if matrix B has:
А. 2 rows
3
B. 2 columns
A.
C. 3 rows
-1
D. 3 columns
В.
2
22. When the inverse of a matrix is multiplied by
the original matrix, it produces the :
A. matrix of cofactors
C.
B. adjoint of the matrix
C. transpose of the matrix
D. identity matrix
3
D.
-3
23. The cofactor for the first elemet in the
coefficient matrix for this system
2.x+3y+3z = 2
19. Let AX =B be a system of linear equations
where A is a3x3. Suppose
4х-3у-62 %3D 2 is:
10х-6у+32 %3D0
det A = 3, det A, = 6 , det A, = -12 and det A, = 27
|3D
А. — 45
then the solution set using Cramer's rule is:
A. x=3, y=2, z = 0
B. x= 2, y=-4 , z=9
В. — 27
С. 27
C. x= 3, y=-15, z= 24
D. 45
D. x=, y=-, z = ;
5
N
Transcribed Image Text:Instruction: Highlight the correct answer
5. The result of the following matrix product
-3 1
0 2
is:
1
3 4 1
4 -5
А.
12
5
13
В.
-6 1
2
С.
4 3
2
D.
13
-6 7
6. The following system of equations is written in
the form AX=B:
x- 4y =-2
3x+y=0
Which of the following matrices correctly
represents matrix A?
-4 -2
A.
1
В.
3
4. Which of the following is FALSE with respect
С.
1
-2 4
to a matrix
-2
D.
3 0
1
7
А. ВВ1 —1
B. B'I = B1
C. B exist if B is a singular matrix
D. B exist if B is a non-singular matrix
-1
2
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