- 1 2x1 − x 2 + — e¯x1 -x1 + 2x2 + + } 1 = −1 ex = 1
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Consider the following nonlinear system.
Take x(0) = (1,1)T and do two iterations of the Newtons method.
Step by step
Solved in 2 steps
- Solution Floating point representation: It is defined as the representation of floating numbers. It includes sign bit, exponent, and mantissa bits. Based on precision it has 2 types. 1. For IEEE 754 single-precision floating-point numbers, what is the exponent of a denormalized floating-point number in decimal? Solution: In IEEE 754 single-precision, exponent bits are 8. Therefore exponent = 2 ^(n-1) -1 = 2^(8-1) -1 = 127 OPTION D 2. For IEEE 754 single-precision floating-point numbers, how many bits for mantissa? Solution: In IEEE 754 single-precision, there are 23 bits for mantissa. sign = 1 bit exponent = 8 bits mantissa = 23 bits 3. For IEEE 754 single-precision floating-point numbers, which of the following is an example of NAN? Solution: In IEEE 754 single-precision, NAN is a special value where all exponents bits are 1's and the mantissa is non zero. a. 1 111 1 111 0000 0000 1101 0000 0000 0000 Exponent is not all 1's. Not a NAN b. 0 111 1 111 1000 0000…Two friends are exchanging messages through regular post mail. They don't want anyone to understand their messages in case anyone read them. The messages are in the form of an array of characters, where each character has a numeric value as illustrated in the below lookup table. GHIJ K LM 6 7 8 A BC DE F 1 2 3 4 9 10 11 12 13 QRS 14 15 16 17 18 19 20 N O P T U v V w X Y 21 22 23 24 25 26 They decided to change the characters in the array in a way that cannot be observed by any accidental reading. They do so as follows: 1- Given the original message, for example: GREETINGS 2- transform the original character to its numeric value 7 18 5 5 20 9 14 7 19 3- For each number, subtracting from its value the value of the first lower value character after it, and if there's no such character they will keep that character without any change. 2 12 5 5 11 2 77 19لتكن المصفوفة [x=[1,4,3,2;8,7,9,0;4,6,7,3 [Y=[1,6,7;5,6,4;7,8,9;0,3,4 [W=[1,3,4,5;7,6,8,9;0,9,1,2;4,5,2,3 اكتب كلا من الايعازات التالية : كون المصفوفة الفرعية من الصفوفةx حيث ان z= 6. 8 9. 9. 2.
- Answer me question 2 don't use chat get didn't work please Answer in detailWhat is the postfix form of the expression ?((x + y) ^ 2) + ((x – 4)/3)Q4/Full the following blanks (1101 1010)BCD(5211) = ( )BCD(3321)=()EX-3=()16 * (1101 1010)BCD(5211) = (1110 1100)BCD(3321)=(1010110)EX-3= (A6)16 (1101 1010)BCD(5211) = (1110 0111)BCD(3321)=(1011001)EX-3= (56)16 (1101 1010)BCD(5211) = (1101 0111)BCD(3321)=(1011001)EX-3= (2B)16 (1101 1010)BCD(5211) = (1011 1110)BCD(3321)=(1000111)EX-3= (44)16 None of them II
- Python code that can check the data if there are negative values and if noneTwo friends are exchanging messages through regular post mail. They don’t want anyone to understand their messages in case anyone read them. The messages are in the form of an array of characters, where each character has a numeric value as illustrated in the below lookup table.//ko age.
- 5: Which one is the correct code among the following codes written in MATLAB » X=[1 45 6; 7 3 2 1;1 9 11 3]; » X=[1 4 5 6; 7 3 2 1;1 911 3 ]; »Y=13 4 1; 8 2 7;9 10 1;11 13 9|; » Y=13 41; 82 7;9 10 1;11 13 9]; »Z=X*Y; >Z=X."Y; » Zinv=inv(Z); > Zinv=inv(Z); »Ztrns=Z'; >Ztrns=Z'; Code 1 Code 4 » X=[1 45 6; 7 3 2 1;19 11 3 6|; »Y=13 4 1 2; 8 2 7;9 10 1;11 13 9|; » Z=X*Y; » Zinv=inv(Z); » X=[14 5 6; 7 3 2 1,1 9 11 3); » Y=13 4 1; 8 2 7;9 10 1;11 13 9]; »Z=X.*Y; » Zinv=inv(Z); >Ztrns=Z'; »Ztrns=Z'; Code 2 Code 3Simplify the following expression, 3 (-8 x –6 × 3) |4 – 12| – (6 – 4)*] 1156 3444 1148 -3468 348PROGRAMMING LANGUAGE: C++