1 2 A= |-1 -1 1 = [ ²3₁ 2 0 1 -2]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
How did we get (1,-1,1) I need to understand I have exam , the question is:
For the eigenvalue ?2 = −1, find a corresponding eigenvector.
![1 2 0
+69
A=-1 -1 1
3 2 -2]
2
-1
-1 -1-> 1
2 -2-
2
2
P÷3433
(€90-8)
(₁)
1-) 2
3 2
x=-y
X=Z
1₂=-1
2
2
1
C
2х+2y=0
-X+z=0
3x +2y-z=0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F574922ea-7d30-4bbb-b384-b46232f01934%2F88e7020b-68f3-4b5b-ba4e-68eaa32494db%2Falml6w3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1 2 0
+69
A=-1 -1 1
3 2 -2]
2
-1
-1 -1-> 1
2 -2-
2
2
P÷3433
(€90-8)
(₁)
1-) 2
3 2
x=-y
X=Z
1₂=-1
2
2
1
C
2х+2y=0
-X+z=0
3x +2y-z=0
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