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(c)
Introduction:
Diffraction refers to various phenomena that occur when a wave encounters an obstacle or opening. It is defined as the bending of waves around the corners of an obstacle or through an aperture into the region of geometrical shadow of the obstacle/aperture.
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- A coal power plant has a rated output of 150 MW and a first law efficiency of 41%. Coal has an energy density of 24 MJ/kg. How many metric tons of coal are wasted by the power plant per hour while running at full capacity (that is, how much of the coal that was burned did not actually contribute to generating electricity)? Express your answer in metric tons of coal.If the average household in a region consumes about 5,250 kWh of energy per year. In the region, the average annual solar energy potential is about 1,450 kWh/m² per year. If solar panels are available in sizes of 1 m x 1 m with an efficiency of 18 %, how many panels will be needed to power a house? (Since you can't have a fraction of panel, always round up you number to the next integer.) Your Answer: Answer2 is 3.79, (Just 3,5,6,7) please
- (I) Write the binary number 01010101 as a decimal numberPlease use one of the following formulas: F=-k∆d f=(1/2π)(√(k/m)) T=2π√(m/k) f=(1/2π)(√(g/L)) T=2π√(L/g) v=d/t v=λf fd=fs(v+vd)/(v-vs) f=1/T T=1/f v=4Lf v=2Lf f=(1/2L)√(FT/μ)(3) The speed of light in vacuum, c, is 3 X 105 km/s and 1 kilometer = 1000 meters. How many Joules of energy are released if 2 kg of matter are converted into energy at 0.1% efficiency? First convert c to units of meters/second: c = 3 x 105 km/s x 1000 m/km = 3 x 108 m/s. Then express efficiency (eff) in decimal terms: eff = 0.001. In this type of problem, the mass/ energy equivalence equation is written as: E = (eff) mc2 Joules,