1 2 3 LE 2+ Ca: F: Li L 4 5 7 6 [ANN] Ne 21

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the numbers above the dot structures, click the numbers of the correct dot structures only.
Ex: if only #1 and 2 are correct, click 1 and 2 only.
1
●2
Ca: F:
2
7
6
3
5
1
2
4
3
H
4
5
7
6
[ANN]
Transcribed Image Text:Using the numbers above the dot structures, click the numbers of the correct dot structures only. Ex: if only #1 and 2 are correct, click 1 and 2 only. 1 ●2 Ca: F: 2 7 6 3 5 1 2 4 3 H 4 5 7 6 [ANN]
Expert Solution
Step 1

1) Calcium (Ca): Its atomic number is 20 and nearest inert configuration number is 18. So, by losing 2 electrons it can attain stability.

Calcium electronic configuration is 1s2 2s2 2p6 3s2 3p6 4s2 and dot structure is Ca  when it loses 2 electrons, the calcium ion will be Ca+2.  The 2 electrons in dot structure of Ca will be given up in Ca+2 and cation will not have any dots. 

So, option 1 is not a right answer

2) Fluorine (F): Its atomic number is 9 and it nearest inert configuration is 10.

It requires one valence electron to reach the inert configuration. It will be surrounded by 7 valence electrons in its elemental state. When it gains one electron then one more electron surrounds the fluorine atom. 

The above dot structure is correct for F-

So, option 2 is right answer

3) Lithium (Li): Its atomic number is 3 and its nearest inert configuration is 2.

It loses one electron to reach the inert configuration and surrounded by one dot electron in elemental state. After losing one electron, Li+ will not be surrounded by any electrons. 

So, Option 3 is not correct answer

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