Can you do question c please 1a. Use the data collected by experiment to calculate a molar enthalpy of reaction formethanol.1Answer:4.38932.02g/mol= 1362molb. Use the value calculated in question 4.a to calculate the standard molar enthalpy offormation for methanol[-279.1 kJ/mol or -367.1 kJ/mol, only one is correct!]Answer:[-598 kJ/mol ]-80.5kJ = -598 kJ/mol0.1362 molCH₂OH+3/202-32H₂0 CH3OHC-393.5)+2mol C-285.8)-(597.9)= -367.1 kJC2600g)c4.189J/g)C21.9-20.5) = 905003= 80.5 KJAnswer:c. Calculate a percentage difference between the value calculated in question 4.b andthe value for the standard molar enthalpy of formation for methanol shown in yourChemistry 30 Data Booklet (This can be found posted on Moodle - you should printoff a copy and keep it handy for all of your assignments, if you have not already doneso)Standard molar enthalpy of formation =CH₂OH(1) -239.2[ 53.5 % ]

The percentage error is calculated by the ratio between the difference between the theoretical and…

1 1 a. Use the data collected by experiment to calculate a molar enthalpy of reaction for methanol. (2600g) (4.1843/g") C219-20.5) = 805003 = 80.5 KJ Answer: 4.389 32.02g/mol = 1362mol [-598 kJ/mol ] -805kJ <- O.1362 mol Answer: b. Use the value calculated in question 4.a to calculate the standard molar enthalpy of formation for methanol [-279.1 kJ/mol or -367.1 kJ/mol, only one is correct!] -598 kJ/mol CH₂OH+3/202-32H₂0 CH 30H C-393.5)+2mol C-285.8)-(597.9) = -367.1 kJ c. Calculate a percentage difference between the value calculated in question 4.b and the value for the standard molar enthalpy of formation for methanol shown in your Chemistry 30 Data Booklet (This can be found posted on Moodle - you should print off a copy and keep it handy for all of your assignments, if you have not already done so) Standard molar enthalpy of formation =CH₂OH(1) -239.2 for methanol [ 53.5 % ]

1 1 a. Use the data collected by experiment to calculate a molar enthalpy of reaction for methanol. (2600g) (4.1843/g") C219-20.5) = 805003 = 80.5 KJ Answer: 4.389 32.02g/mol = 1362mol [-598 kJ/mol ] -805kJ <- O.1362 mol Answer: b. Use the value calculated in question 4.a to calculate the standard molar enthalpy of formation for methanol [-279.1 kJ/mol or -367.1 kJ/mol, only one is correct!] -598 kJ/mol CH₂OH+3/202-32H₂0 CH 30H C-393.5)+2mol C-285.8)-(597.9) = -367.1 kJ c. Calculate a percentage difference between the value calculated in question 4.b and the value for the standard molar enthalpy of formation for methanol shown in your Chemistry 30 Data Booklet (This can be found posted on Moodle - you should print off a copy and keep it handy for all of your assignments, if you have not already done so) Standard molar enthalpy of formation =CH₂OH(1) -239.2 for methanol [ 53.5 % ]

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter7: Chemical Energy

Section: Chapter Questions

Problem 88E

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