05 The stress concentration factor, K for a flat bar with a centric hole under axial loading is: 3 -3.13 (27) +3.66 (2)² -1.53 (2) - D where: K= 3.00-3.13 r = radius of the hole, and D= the width of the bar, If D=75 mm, approximate the value of r to obtain K = 3.5. (a) Determine your result using Bisection and Secant method. All data /values shall be in 4-decimal place. Do iteration up to five (5) iteration or stop if two consecutive r values are less than 0.001. (Hint: r is somewhere between 4 and 6 mm. Use this value as initial guess) KON (b) Discuss the differences of the answers from Q5(a). J

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Chapter2: Second-order Linear Odes
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05
The stress concentration factor, K for a flat bar with a centric hole under axial loading is:
3
-3.13 (2) + 3.66 (27)²-1.53 (2)
D
where:
K= 3.00-3.13
r = radius of the hole, and
D=the width of the bar,
If D=75 mm, approximate the value of r to obtain K = 3.5.
(a) Determine your result using Bisection and Secant method. All data /values shall be in
4-decimal place. Do iteration up to five (5) iteration or stop if two consecutive r values
are less than 0.001. (Hint: r is somewhere between 4 and 6 mm. Use this value as initial
guess)
KON
(b)
Discuss the differences of the answers from Q5(a).
||
Transcribed Image Text:05 The stress concentration factor, K for a flat bar with a centric hole under axial loading is: 3 -3.13 (2) + 3.66 (27)²-1.53 (2) D where: K= 3.00-3.13 r = radius of the hole, and D=the width of the bar, If D=75 mm, approximate the value of r to obtain K = 3.5. (a) Determine your result using Bisection and Secant method. All data /values shall be in 4-decimal place. Do iteration up to five (5) iteration or stop if two consecutive r values are less than 0.001. (Hint: r is somewhere between 4 and 6 mm. Use this value as initial guess) KON (b) Discuss the differences of the answers from Q5(a). ||
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