Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
i need help with 5b, im not sure where i went wrong

Transcribed Image Text:5.
formula of this compound.
formula of this species.
A Few Reminders:
Always use a quality Periodic Table when solving problems for
this course, such as the one posted to Blackboard. Do not use
12 g/mol as the atomic weight for carbon ... 12.0107 g/mol is
far more precise.
Also, always include units in your work, and don't forget to
watch the significant digits in your computations.

Transcribed Image Text:%3D
Males of W= 4100053577
193.8419/mal
masslo6175 g
molesbioo335-zmol 14niol
Moles o0omol
molesd
mol
moles of F=
Ch
13.9984039/201 =0.02014,
6.999imol!
Da
3.
mol
I mol
owing questions
merical answer
leaf paper. Jus
0.0638g
0.145190.05245
estions: Cons
ery SnCla unit
I wolc
luotco
wales of
the mass per
the mass pe
he mass pere
e the molar
moles of- oiosaha
5324.
any joules of
=0.006994mol
C to 122 °
g sample of
C, what will
mofc=lo,003297oucol 1078g/mol) =0103960, a
moftH=(0.006594 molXl.00947glarol)=D010066469
moto-0.0633g-oigt0.0066469)c0.0308as
ach of the
eous mixt
10:03960
moles of o = 5,99943a/ad = 0.00192, mol
Sub
0.0308
co.030849
inside
rowr
moleso.003297omolo.0065 94 wel o00192,mel.
esles. mol
PIO
AJIS
10.4
of
Expert Solution

Step 1
There is error in calculation of mass of oxygen
Mass of O =0.0638-(0.0396+0.00664)
= 0.01756 g
Moles of O = 0.01756/16
= 0.0010975 mol
Step by step
Solved in 3 steps

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